VBA: Change variable within loop for next contant string formula

FryGirl

Well-known Member
Joined
Nov 11, 2008
Messages
1,368
Office Version
  1. 365
  2. 2016
Platform
  1. Windows
I have about 10 Const as String formulas and need to loop thru them column by column. It starts with column 3.

The part in Red, need to change in the loop, but can't get the right syntax to change the last digit of the sFormula to grab the next formula for the next column.


Code:
Sub dkdk()

    Const sFormula3     As String = "=My_a_Value"
    Const sFormula4     As String = "=(COUNTIFS(Data!$T$2:$T$638675,$B2,Data!P$2:P$638675,D$1)/60)*1.2138"
    Const sFormula5 etc....

    Dim i As Long

    With Sheet7     
   
        For i = 3 To 12
            .Range(Cells(2, i), Cells(LR, i)).Formula = [COLOR=#ff0000]sFormula1[/COLOR]
            .Columns(i).Value = .Columns(i).Value
        Next i

    End With

End Sub

I tried sFormula & i, but that failed
 
Last edited:

Excel Facts

Repeat Last Command
Pressing F4 adds dollar signs when editing a formula. When not editing, F4 repeats last command.
Try this instead:
Code:
Option Base 1


Sub dkdk()
    Dim Arr(10, 1) As String
    Arr(1, 1) = "=My_a_Value"
    Arr(2, 1) = "=(COUNTIFS(Data!$T$2:$T$638675,$B2,Data!P$2:P$638675,D$1)/60)*1.2138"
    Arr(3, 1) = etc....


    With Sheet7
   
        For i = 3 To 12
            .Range(Cells(2, i), Cells(LR, i)).Formula = Arr(i - 2, 1)
            .Columns(i).Value = .Columns(i).Value
        Next i


    End With


End Sub
 
Upvote 0
You can't work with variables like that, try using an array instead.
Code:
Sub dkdk()
Dim i As Long
Dim sFormulas As Variant

    
    Const sFormula3     As String = "=My_a_Value"
    Const sFormula4     As String = "=(COUNTIFS(Data!$T$2:$T$638675,$B2,Data!P$2:P$638675,D$1)/60)*1.2138"

    sFormulas = Array(sformula2, sFormula4) ' add the other constants

    With Sheet7
   
        For i = 3 To 12
            .Range(Cells(2, i), Cells(LR, i)).Formula = sFormulas(i - 3)
            .Columns(i).Value = .Columns(i).Value
        Next i

    End With

End Sub
 
Upvote 0
Hi Chris,

That works absolutely perfect. Thank you for your time.
 
Upvote 0
Hi Norie,

That worked extremely well also. Thank you for your time.
 
Last edited:
Upvote 0

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