Using Find to test if element exist in an Range Array

Erick

Active Member
Joined
Feb 26, 2003
Messages
362
Hi all, I am looking to use the 'Find' vba function to test if an element exist in a range array but I am getting a 'Type mismatch error'.

When I swap my array from a range to a list, it works.

Please help.
VBA Code:
Sub FindBob()
   'Create Array
   Dim a As String
   Dim strName As Variant
   
   strName = Range("A1:A5") 'is generates a Type mismatch error - the range contains the same elements as the list below
   
   'strName = Array("Bob Smith", "John Davies", "Fred Jones", "Steve Jenkins", "Bob Williams") - this method works
   
   'declare a variant to store the filter data in
   Dim strSubNames  As Variant

  'filter the original array
 
   strSubNames = Filter(strName, "Bob")

   'if you UBound value is greater than -1, then the value has been found
   If UBound(strSubNames, 1) > -1 Then MsgBox ("I found Bob")
End Sub
 

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Change
VBA Code:
strName = Range("A1:A5")
to
VBA Code:
strName = Application.Transpose(Range("A1:A5"))

Also be aware that if Bob Smith and Bob Williams did not appear in the list but Bobette Jones did, the message box would still say "I found Bob"
 
Upvote 0
Thanks Peter and Joe. I have a large data, which of the 2 options (match or filter) is more efficient?
Also, I tried the match option as you suggested, with the line of code below but I am getting an Error 2042, which I read was effectively an N/A result.

"If Not IsError(Application.Match("Bob", strName, 0)) Then MsgBox ("I found Bob again")"
 
Upvote 0
Thanks Peter and Joe. I have a large data, which of the 2 options (match or filter) is more efficient?
Also, I tried the match option as you suggested, with the line of code below but I am getting an Error 2042, which I read was effectively an N/A result.

"If Not IsError(Application.Match("Bob", strName, 0)) Then MsgBox ("I found Bob again")"
That is not quite the way they show in the code. They show a format of:
VBA Code:
If IsNumeric(Application.Match("Bob", strName, 0)) Then MsgBox ("I found Bob again")"
and that is assuming that strName is an array, and not a range.
 
Upvote 0
Can you confirm whether or not you want to show "Found" if the text being searched for is a sub-string of a longer text as in the example at the bottom of my previous post?
 
Upvote 0

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