TerrorTot38
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- Feb 2, 2022
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Hi All,
I have a maths question I need your help with.
I'm trying to generate 12 unique pairs for Badminton Doubles to not have the following:
However I make changes to one thing and either no unique pairs or in my example above Player 5 against 7,8 and 11.
I have represented the data to show the players and opponents across the games.
Could anyone advise if this iteration is possible or the closest I'm going to get is what I have.
I have a maths question I need your help with.
I'm trying to generate 12 unique pairs for Badminton Doubles to not have the following:
- Player 12 not playing Player 4 three times (example Game 4, Game 5 and Game 6)
- Player 5 not playing Player 7, 8 and 11 more than once such as 7,8, 7,11 or 8,11 but not all 3 (shown below)
Match:1 | Court 1 | Court 2 | Court 3 |
9 & 1 | 11 & 2 | 12 & 7 | |
10 & 6 | 4 & 5 | 8 & 3 | |
Match:2 | Court 1 | Court 2 | Court 3 |
3 & 5 | 12 & 10 | 1 & 4 | |
7 & 8 | 11 & 6 | 2 & 9 | |
Match:3 | Court 1 | Court 2 | Court 3 |
12 & 2 | 4 & 7 | 6 & 8 | |
3 & 9 | 5 & 1 | 10 & 11 | |
Match:4 | Court 1 | Court 2 | Court 3 |
1 & 3 | 12 & 8 | 10 & 2 | |
5 & 6 | 9 & 4 | 11 & 7 | |
Match:5 | Court 1 | Court 2 | Court 3 |
10 & 1 | 12 & 6 | 8 & 11 | |
3 & 4 | 7 & 2 | 9 & 5 |
However I make changes to one thing and either no unique pairs or in my example above Player 5 against 7,8 and 11.
I have represented the data to show the players and opponents across the games.
Game 3 | Game 3 | Game 4 | Game 4 | Game 5 | Game 5 | Game 7 | Game 7 | Game 10 | Game 10 | |
1 | 10 | 6 | 2 | 9 | 4 | 7 | 5 | 6 | 3 | 4 |
2 | 4 | 5 | 1 | 4 | 3 | 9 | 11 | 7 | 12 | 6 |
3 | 12 | 7 | 7 | 8 | 12 | 2 | 5 | 6 | 10 | 1 |
4 | 11 | 2 | 2 | 9 | 5 | 1 | 12 | 8 | 10 | 1 |
5 | 11 | 2 | 7 | 8 | 4 | 7 | 1 | 3 | 8 | 11 |
6 | 9 | 1 | 12 | 10 | 10 | 11 | 1 | 3 | 7 | 2 |
7 | 8 | 3 | 3 | 5 | 5 | 1 | 10 | 2 | 12 | 6 |
8 | 12 | 7 | 3 | 5 | 10 | 11 | 9 | 4 | 9 | 5 |
9 | 10 | 6 | 1 | 4 | 12 | 2 | 12 | 8 | 8 | 11 |
10 | 9 | 1 | 11 | 6 | 6 | 8 | 11 | 7 | 3 | 4 |
11 | 4 | 5 | 12 | 10 | 6 | 8 | 10 | 2 | 9 | 5 |
12 | 8 | 3 | 11 | 6 | 3 | 9 | 9 | 4 | 7 | 2 |
Could anyone advise if this iteration is possible or the closest I'm going to get is what I have.