Troubleshooting Loop In PictureInsert Code

DataBlake

Well-known Member
Joined
Jan 26, 2015
Messages
781
Office Version
  1. 2016
Platform
  1. Windows
Code:
Sub URLPictureInsert()
    Dim Pshp As Shape
    Dim i As Long
    Dim lastRow As Long
    Dim urlRng As Range
    Dim trgtRng As Range
    
    
lastRow = Range("A" & Rows.Count).End(xlUp).Row
For i = 2 To lastRow

   Set urlRng = Range("B" & i)
   Set trgtRng = Range("C" & i)

If urlRng = "" Then Range("H" & i).Value = 0
If urlRng = "" Then GoTo lastline
    
        filenam = urlRng
 On Error Resume Next
      ActiveSheet.Pictures.Insert(filenam).Select
        On Error Resume Next
        Set Pshp = Selection.ShapeRange.Item(1)
        On Error GoTo 0
        If Pshp Is Nothing Then GoTo lab
        Range("H" & i).Value = 1
    With Pshp
            .LockAspectRatio = msoFalse
            .Width = 15
            .Height = 15
            .Top = trgtRng.Top
            .Left = trgtRng.Left
    End With
lab:
    If Pshp Is Nothing Then Range("H" & i).Value = 0
    Set Pshp = Nothing
lastline:
    Next i
End Sub

So i have this code that inserts images into column C but there is a problem in that it keeps putting the last correct image at the last incorrect image. It creates this +1 offset by doing this and i'm unsure of where in my code this is happening. I will attach a picture to illustrate.

As well is there a surefire way to put "0" in column H if the image does not work? meaning the url does in fact go to a webpage, but the image does not exist there. Image not found still equates to a "1" in column H

example images used:
https://cookieandkate.com/images/2018/04/delicious-vegetarian-tacos-recipe.jpg (correct image)
https://cookieandkate.com/images/2018/04/delicious-vegetarian-tacos-ree (incorrect image that still produces a "1")
https://i733.photobucket.com/albums/ww338/ShopLAOnline/back_heyhole_top_ella_red.jpg (incorrect image that still produces a "1")


O0aT6PA.png
 

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At a guess the when an image doesn't exist the previous image is still selected, try
Code:
    If Pshp Is Nothing Then Range("H" & i).Value = 0
    Set Pshp = Nothing
    [COLOR=#ff0000]Range("a1").Select[/COLOR]
 
Upvote 0
At a guess the when an image doesn't exist the previous image is still selected, try
Code:
    If Pshp Is Nothing Then Range("H" & i).Value = 0
    Set Pshp = Nothing
    [COLOR=#ff0000]Range("a1").Select[/COLOR]

huh.... thats a strange interaction but i'll take it, thank you.
that solved both issues
 
Upvote 0
You're welcome & thanks for the feedback
 
Upvote 0
How about
Code:
Sub URLPictureInsert()
    Dim Pshp As Shape
    Dim i As Long
    Dim lastRow As Long
    Dim urlRng As Range
    Dim trgtRng As Range
    
    
lastRow = Range("A" & Rows.Count).End(xlUp).Row
For i = 2 To lastRow

   Set urlRng = Range("B" & i)
   Set trgtRng = Range("C" & i)

If urlRng = "" Then Range("H" & i).Value = 0
If urlRng = "" Then GoTo lastline
    
        filenam = urlRng
      On Error Resume Next
      With ActiveSheet.Pictures.Insert(filenam)
             If Err = 1004 Then Range("H" & i) = 0 Else Range("H" & i) = 1
            .LockAspectRatio = msoFalse
            .Width = 15
            .Height = 15
            .Top = trgtRng.Top
            .Left = trgtRng.Left
    End With
    On Error GoTo 0
lastline:
    Next i
End Sub
 
Upvote 0
You're welcome & thanks for the feedback
 
Upvote 0

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