Transpose VBA not working

devj364

New Member
Joined
Apr 30, 2018
Messages
4
Hello All,

I am having an issue with this little piece of code. For some reason it is only transposing the information every other line and has been driving me crazy. I am still pretty new to VBA, so any help would be greatly appreciated.
Code:
Dim numrows As Integer
Dim counter As Integer
Dim x As Integer
Dim y As Integer
Dim trans As Integer


numrows = Range("A11", Range("A1").End(xlDown)).Rows.Count


Range("A11:D11").Select


counter = 1
 
    Do Until x = numrows
    trans = counter * 4
    
        counter = counter + 1
        Application.CutCopyMode = True
        Selection.Copy
        ActiveCell.Offset(1, 0).Select
        Range(Cells(Selection.Row, 1), Cells(Selection.Row, 4)).Select


            Application.Wait Now + #12:00:01 AM#
       
            
            Range("g9:g12").Offset(trans, 0).PasteSpecial Transpose:=True


            x = x + 1
    




Application.Wait Now + #12:00:01 AM#


Loop


End Sub
Thank you in advance.
 
Last edited by a moderator:

Excel Facts

Ambidextrous Undo
Undo last command with Ctrl+Z or Alt+Backspace. If you use the Undo icon in the QAT, open the drop-down arrow to undo up to 100 steps.
You haven't said what you are trying to do, but looking at your code , I think you are trying to get columns ( A to D) inot one column (G)
this code will do that for you and it is using variant arrays so it will be much much faster than the way you are doing it.

Code:
Sub test()
numrows = Cells(Rows.Count, "A").End(xlUp).Row


inarr = Range("A1:D" & numrows)
Range("G9:G" & 4 * (numrows - 10)) = ""
outarr = Range("G9:G" & 10 + 4 * (numrows - 10))
indi = 1
For i = 11 To numrows
  For j = 1 To 4
    outarr(indi, 1) = inarr(i, j)
    indi = indi + 1
  Next j
Next i
Range("G9:G" & 10 + 4 * (numrows - 10)) = outarr


End Sub
 
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