Split first word only if it is part of a range.

topi1

Active Member
Joined
Aug 6, 2014
Messages
252
Office Version
  1. 2010
In the following example, I have a range of values in the column E. data in the column A. In the columns B and C I have entered formulas (arrived by working stepwise on several columns and then combining it). Everything works well and extracts first word from A into column B only if it is part of the range in the column E. And it leaves the rest in the column C.
Is it possible to have a vba which can do the same thing? Thank you.

rscripto11.xlsm
ABCDE
42GM #1 GM #1One
43Dodge #4 Dodge #4Two
44Ford #2 Ford #2Three
45Jeep #3 Jeep #3Four
46One DodgeOneDodgeFive
47Two DodgeTwoDodge
48Two JeepTwoJeep
49One DodgeOneDodge
50One JeepOneJeep
51Two JeepTwoJeep
Sheet6
Cell Formulas
RangeFormula
B42:B51B42=IF((COUNTIF($E$42:$E$51,IFERROR(LEFT(A42, FIND(" ", A42)-1), A42))=1),IFERROR(LEFT(A42, FIND(" ", A42)-1), A42),"")
C42:C51C42=IF((COUNTIF($E$42:$E$51,IFERROR(LEFT(A42, FIND(" ", A42)-1), A42))=1),IF((ISERROR(SUBSTITUTE(A42,LEFT(A42,FIND(" ",A42)),""))=FALSE),SUBSTITUTE(A42,LEFT(A42,FIND(" ",A42)),""),""),A42)
 

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Try:
VBA Code:
Sub SplitFirstWord()
    Application.ScreenUpdating = False
    Dim fnd As Range, v As Variant, i As Long
    v = Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 2).Value
    For i = LBound(v) To UBound(v)
        Set fnd = Range("E42:E46").Find(Split(v(i, 1), " ")(0))
        If Not fnd Is Nothing Then
            Range("B" & i + 41) = Split(v(i, 1), " ")(0)
        End If
    Next i
    Application.ScreenUpdating = True
End Sub
 
Upvote 0
Try:
VBA Code:
Sub SplitFirstWord()
    Application.ScreenUpdating = False
    Dim fnd As Range, v As Variant, i As Long
    v = Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 2).Value
    For i = LBound(v) To UBound(v)
        Set fnd = Range("E42:E46").Find(Split(v(i, 1), " ")(0))
        If Not fnd Is Nothing Then
            Range("B" & i + 41) = Split(v(i, 1), " ")(0)
        End If
    Next i
    Application.ScreenUpdating = True
End Sub
@mumps Thank you for your prompt help. Can you please help me with two issues?
1) It did not extract the rest. Column C remains empty.
2) recognize numbers as first word in case in the column E it has a cell that has 7 instead of seven. The current vba does not recognize 7. I don't know how to use excel formula TEXT for vba.
Thank you.
 
Upvote 0
Code.> Adjust the ranges as required.
VBA Code:
Sub GetFirstword()
Dim A, R, M, ary, Lr&, T&, Ta&
Lr = Range("A" & Rows.Count).End(xlUp).Row
A = Range("A3:A" & Lr)
ReDim R(1 To UBound(A, 1), 1 To 1)
ary = Range("E3:E7")

With CreateObject("scripting.dictionary")
For T = 1 To UBound(ary, 1)
.Add ary(T, 1), T
Next T

For Ta = 1 To UBound(A, 1)
M = Split(A(Ta, 1), " ")
If .exists(M(0)) Then R(Ta, 1) = M(0)
Next Ta
End With

Range("B3:B" & Lr) = R
End Sub
 
Upvote 0
Code.> Adjust the ranges as required.
VBA Code:
Sub GetFirstword()
Dim A, R, M, ary, Lr&, T&, Ta&
Lr = Range("A" & Rows.Count).End(xlUp).Row
A = Range("A3:A" & Lr)
ReDim R(1 To UBound(A, 1), 1 To 1)
ary = Range("E3:E7")

With CreateObject("scripting.dictionary")
For T = 1 To UBound(ary, 1)
.Add ary(T, 1), T
Next T

For Ta = 1 To UBound(A, 1)
M = Split(A(Ta, 1), " ")
If .exists(M(0)) Then R(Ta, 1) = M(0)
Next Ta
End With

Range("B3:B" & Lr) = R
End Sub
@kvsrinivasamurthy I got an error in the following line.
.Add ary(T, 1), T
 
Upvote 0
Try:
VBA Code:
Sub SplitFirstWord()
    Application.ScreenUpdating = False
    Dim fnd As Range, v As Variant, i As Long
    v = Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 2).Value
    For i = LBound(v) To UBound(v)
        Set fnd = Range("E42:E46").Find(Split(v(i, 1), " ")(0))
        If fnd Is Nothing Then
            Range("C" & i + 41) = v(i, 1)
        Else
            Range("B" & i + 41) = Split(v(i, 1), " ")(0)
            Range("C" & i + 41) = Split(v(i, 1), " ")(1)
        End If
    Next i
    Application.ScreenUpdating = True
End Sub
 
Upvote 0
Solution
Try.
VBA Code:
Sub Macro1()
Dim A, R, M, ary, Lr&, T&, Ta&
Lr = Range("A" & Rows.Count).End(xlUp).Row
A = Range("A3:A" & Lr)
ReDim R(1 To UBound(A, 1), 1 To 1)
ary = Range("E3:E7")

With CreateObject("scripting.dictionary")
For T = 1 To UBound(ary, 1)
If ary(T, 1) <> "" Then .Add ary(T, 1), T
Next T

For Ta = 1 To UBound(A, 1)
If A(Ta, 1) <> "" Then
M = Split(A(Ta, 1), " ")
If .exists(M(0)) Then R(Ta, 1) = M(0)
End If
Next Ta
End With

Range("B3:B" & Lr) = R
End Sub
 
Upvote 0
VBA Code:
Sub jec()
 Dim ar, ar2, j As Long, jj As Long
 ar = Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 3)
 ar2 = Range("E42:E46")
 For j = 1 To UBound(ar)
   ar(j, 3) = ar(j, 1)
   For jj = 1 To UBound(ar2)
     If InStr(ar(j, 1), ar2(jj, 1)) Then
       ar(j, 2) = Split(ar(j, 1))(0)
       ar(j, 3) = Split(ar(j, 1))(1)
       Exit For
     End If
   Next
 Next
 Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 3) = ar
End Sub
 
Upvote 0
Try.
VBA Code:
Sub Macro1()
Dim A, R, M, ary, Lr&, T&, Ta&
Lr = Range("A" & Rows.Count).End(xlUp).Row
A = Range("A3:A" & Lr)
ReDim R(1 To UBound(A, 1), 1 To 1)
ary = Range("E3:E7")

With CreateObject("scripting.dictionary")
For T = 1 To UBound(ary, 1)
If ary(T, 1) <> "" Then .Add ary(T, 1), T
Next T

For Ta = 1 To UBound(A, 1)
If A(Ta, 1) <> "" Then
M = Split(A(Ta, 1), " ")
If .exists(M(0)) Then R(Ta, 1) = M(0)
End If
Next Ta
End With

Range("B3:B" & Lr) = R
End Sub
Sorry. It did not work. Didn't give an error message but didn't do anything to columns B or C.
 
Upvote 0
Try:
VBA Code:
Sub SplitFirstWord()
    Application.ScreenUpdating = False
    Dim fnd As Range, v As Variant, i As Long
    v = Range("A42", Range("A" & Rows.Count).End(xlUp)).Resize(, 2).Value
    For i = LBound(v) To UBound(v)
        Set fnd = Range("E42:E46").Find(Split(v(i, 1), " ")(0))
        If fnd Is Nothing Then
            Range("C" & i + 41) = v(i, 1)
        Else
            Range("B" & i + 41) = Split(v(i, 1), " ")(0)
            Range("C" & i + 41) = Split(v(i, 1), " ")(1)
        End If
    Next i
    Application.ScreenUpdating = True
End Sub
@mumps It works great as long the value in E is not a number. Is there a solution? I tried to add some columns and tried to use TEXT formula, but it did not work. TY.
 
Upvote 0

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