Split cell contents in different sets

P

Pete2020

Board Regular
Joined
Apr 25, 2020
Messages
68
Office Version
  1. 2016
Platform
  1. Windows
I am looking for a Excel Formula or function or VBA which is simple to understand. The actual data is Text and not a Numeric values

The cell contents is to be divided into different sets with flower brackets and a comma separator.
It should separate the data equally based on values in available based on "|" delimiter

Ex: Column A Row 1 ( Full range has around 10k Rows)
1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|

After Applying formula or VBA code - The values shoule be equally divided and if not divisible it should fall under another curly bracket

In Column B Row1 the data should present with curly Brackets based on groups i mentioned in VBA or formula
{1|2|3|4|5},{6|7|8|9|10},{11|12|13|14|15},{16|17|18|19|20}
 

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Try this
VBA Code: 
Sub Pete2020_Split()

Dim DTA() As Variant, SSP() As String, G As Long, K As Long, Build_STR As String, D_Count As Long, Output() As String

With Application
    .ScreenUpdating = False
    .Calculation = xlCalculationManual
End With

DTA = ActiveSheet.UsedRange.Value2

Const Delimiter As String = "|"

ReDim Output(1 To UBound(DTA, 1), 1 To 1)

For G = 1 To UBound(DTA, 1)

    SSP = Split(DTA(G, 1), "|")
    
    For K = LBound(SSP) To UBound(SSP)
    
        Select Case K

            Case LBound(SSP)

                Build_STR = "{" & SSP(K)

            Case UBound(SSP)
            
                If SSP(K) <> vbNullString Then
                    Build_STR = Build_STR & Delimiter & SSP(K) & "}"
                Else
                    Build_STR = Build_STR & "}"
                End If
                
                D_Count = 0
                
            Case Else
            
                Select Case D_Count 'count of "|" in the current group
                
                    Case 4
                    
                        Build_STR = Build_STR & "},{" & SSP(K)
                        D_Count = 0
                        
                    Case Else
                    
                        Build_STR = Build_STR & Delimiter & SSP(K)
                        D_Count = D_Count + 1
                        
                End Select

        End Select
        
    Next K
    
    Output(G, 1) = Build_STR
    Build_STR = vbNullString
    
Next G

ActiveSheet.Range("B1").Value2 = Output

With Application
    .ScreenUpdating = True
    .Calculation = xlCalculationAutomatic
End With

End Sub
 
Upvote 0
Pete2020 said:
1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|
Click to expand...

What are the characteristics or patterns to divide the groups, your example can be divided in several ways:

{1|2|3|4|5|6|7|8|9|10} , {11|12|13|14|15|16|17|18|19|20} (2 groups of 10, are equal groups)
or
{1|2|3|4} , {5|6|7|8} , {9|10|11|12} , {13|14|15|16} , {17|18|19|20} (5 groups of 4, are equal groups)

And in the following example what would be the grouping:
1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|
 
Upvote 0
t
DanteAmor said:
What are the characteristics or patterns to divide the groups, your example can be divided in several ways:

{1|2|3|4|5|6|7|8|9|10} , {11|12|13|14|15|16|17|18|19|20} (2 groups of 10, are equal groups)
or
{1|2|3|4} , {5|6|7|8} , {9|10|11|12} , {13|14|15|16} , {17|18|19|20} (5 groups of 4, are equal groups)

And in the following example what would be the grouping:
1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|
Click to expand...

The Answer is 4 groups of 5 .

It is more helpful if the formula or VBA should provide a facility to update the groups to be splitted.
 
Upvote 0
MoshiM said:
Try this
VBA Code: 
Sub Pete2020_Split()

Dim DTA() As Variant, SSP() As String, G As Long, K As Long, Build_STR As String, D_Count As Long, Output() As String

With Application
    .ScreenUpdating = False
    .Calculation = xlCalculationManual
End With

DTA = ActiveSheet.UsedRange.Value2

Const Delimiter As String = "|"

ReDim Output(1 To UBound(DTA, 1), 1 To 1)

For G = 1 To UBound(DTA, 1)

    SSP = Split(DTA(G, 1), "|")
   
    For K = LBound(SSP) To UBound(SSP)
   
        Select Case K

            Case LBound(SSP)

                Build_STR = "{" & SSP(K)

            Case UBound(SSP)
           
                If SSP(K) <> vbNullString Then
                    Build_STR = Build_STR & Delimiter & SSP(K) & "}"
                Else
                    Build_STR = Build_STR & "}"
                End If
               
                D_Count = 0
               
            Case Else
           
                Select Case D_Count 'count of "|" in the current group
               
                    Case 4
                   
                        Build_STR = Build_STR & "},{" & SSP(K)
                        D_Count = 0
                       
                    Case Else
                   
                        Build_STR = Build_STR & Delimiter & SSP(K)
                        D_Count = D_Count + 1
                       
                End Select

        End Select
       
    Next K
   
    Output(G, 1) = Build_STR
    Build_STR = vbNullString
   
Next G

ActiveSheet.Range("B1").Value2 = Output

With Application
    .ScreenUpdating = True
    .Calculation = xlCalculationAutomatic
End With

End Sub
Click to expand...


Moshi, Once again thank You for giving macro.The VBA has hard coded.

I Kindly request to provide the macro,in such a way i can modify the No of groups it has to split.
 
Upvote 0
Pete2020 said:
It is more helpful if the formula or VBA should provide a facility to update the groups to be splitted.
Click to expand...

There are always 20 data and they are always divided into 5 groups of 4?

Or to which you refer with "facility" you could give more examples of what you have and what you expect from the result.
 
Upvote 0
Look for the variable Number_of_Elements_in_Group on the left and the corresponding comment in the code.
VBA Code: 
Sub Pete2020_Split()

Dim DTA() As Variant, SSP() As String, G As Long, K As Long, Build_STR As String, _
D_Count As Long, Output() As String, Number_of_Elements_in_Group As Long

With Application
    .ScreenUpdating = False
    .Calculation = xlCalculationManual
End With

Number_of_Elements_in_Group = 5
'Or you can retrieve value from a cell like
'Number_of_Elements_in_Group = activesheet.range("C1").VALUE2
'Or from an inputbox.... Number_of_Elements_in_Group = clng(application.InputBox("Input number of of elements per group. Must be a number."))
DTA = ActiveSheet.UsedRange.Value2

Const Delimiter As String = "|"

ReDim Output(1 To UBound(DTA, 1), 1 To 1)

Number_of_Elements_in_Group=Number_of_Elements_in_Group-1

For G = 1 To UBound(DTA, 1)

    SSP = Split(DTA(G, 1), "|")
   
    For K = LBound(SSP) To UBound(SSP)
   
        Select Case K

            Case LBound(SSP)

                Build_STR = "{" & SSP(K)

            Case UBound(SSP)
           
                If SSP(K) <> vbNullString Then
                    Build_STR = Build_STR & Delimiter & SSP(K) & "}"
                Else
                    Build_STR = Build_STR & "}"
                End If
               
                D_Count = 0
               
            Case Else
           
                Select Case D_Count 'count of "|" in the current group
               
                    Case Number_of_Elements_in_Group
                   
                        Build_STR = Build_STR & "},{" & SSP(K)
                        D_Count = 0
                       
                    Case Else
                   
                        Build_STR = Build_STR & Delimiter & SSP(K)
                        D_Count = D_Count + 1
                       
                End Select

        End Select
       
    Next K
   
    Output(G, 1) = Build_STR
    Build_STR = vbNullString
   
Next G

ActiveSheet.Range("B1").Value2 = Output

With Application
    .ScreenUpdating = True
    .Calculation = xlCalculationAutomatic
End With

End Sub
 
Last edited:
Upvote 0
MoshiM said:
Look for the variable Number_of_Elements_in_Group on the left and the corresponding comment in the code.
VBA Code: 
Sub Pete2020_Split()

Dim DTA() As Variant, SSP() As String, G As Long, K As Long, Build_STR As String, _
D_Count As Long, Output() As String, Number_of_Elements_in_Group As Long

With Application
    .ScreenUpdating = False
    .Calculation = xlCalculationManual
End With

Number_of_Elements_in_Group = 5
'Or you can retrieve value from a cell like
'Number_of_Elements_in_Group = activesheet.range("C1").VALUE2
'Or from an inputbox.... Number_of_Elements_in_Group = clng(application.InputBox("Input number of of elements per group. Must be a number."))
DTA = ActiveSheet.UsedRange.Value2

Const Delimiter As String = "|"

ReDim Output(1 To UBound(DTA, 1), 1 To 1)

Number_of_Elements_in_Group=Number_of_Elements_in_Group-1

For G = 1 To UBound(DTA, 1)

    SSP = Split(DTA(G, 1), "|")
  
    For K = LBound(SSP) To UBound(SSP)
  
        Select Case K

            Case LBound(SSP)

                Build_STR = "{" & SSP(K)

            Case UBound(SSP)
          
                If SSP(K) <> vbNullString Then
                    Build_STR = Build_STR & Delimiter & SSP(K) & "}"
                Else
                    Build_STR = Build_STR & "}"
                End If
              
                D_Count = 0
              
            Case Else
          
                Select Case D_Count 'count of "|" in the current group
              
                    Case Number_of_Elements_in_Group
                  
                        Build_STR = Build_STR & "},{" & SSP(K)
                        D_Count = 0
                      
                    Case Else
                  
                        Build_STR = Build_STR & Delimiter & SSP(K)
                        D_Count = D_Count + 1
                      
                End Select

        End Select
      
    Next K
  
    Output(G, 1) = Build_STR
    Build_STR = vbNullString
  
Next G

ActiveSheet.Range("B1").Value2 = Output

With Application
    .ScreenUpdating = True
    .Calculation = xlCalculationAutomatic
End With

End Sub
Click to expand...

Thank You Moshi.
 
Upvote 0
Here another macro for you to consider.

In this line you can set the number of elements for each group
If n = 5 Then

VBA Code: 
Sub splitCell()
  Dim a As Variant, b As Variant, c As String, sItems As Variant
  Dim i As Long, n As Long, j As Long
  a = Range("A1", Range("A" & Rows.Count).End(3)).Value2
  ReDim b(1 To UBound(a), 1 To 1)
  '
  For i = 1 To UBound(a)
    sItems = Split(a(i, 1), "|")
    c = "{"
    n = 0
    For j = 0 To UBound(sItems) - 1
      If n = 5 Then
        c = Left(c, Len(c) - 1) & "},{"
        n = 0
      End If
      c = c & sItems(j) & "|"
      n = n + 1
    Next
    b(i, 1) = Left(c, Len(c) - 1) & "}"
  Next
  '
  Range("B1").Resize(UBound(a)).Value = b
End Sub
 
Upvote 0
DanteAmor said:
Here another macro for you to consider.

In this line you can set the number of elements for each group
If n = 5 Then

VBA Code: 
Sub splitCell()
  Dim a As Variant, b As Variant, c As String, sItems As Variant
  Dim i As Long, n As Long, j As Long
  a = Range("A1", Range("A" & Rows.Count).End(3)).Value2
  ReDim b(1 To UBound(a), 1 To 1)
  '
  For i = 1 To UBound(a)
    sItems = Split(a(i, 1), "|")
    c = "{"
    n = 0
    For j = 0 To UBound(sItems) - 1
      If n = 5 Then
        c = Left(c, Len(c) - 1) & "},{"
        n = 0
      End If
      c = c & sItems(j) & "|"
      n = n + 1
    Next
    b(i, 1) = Left(c, Len(c) - 1) & "}"
  Next
  '
  Range("B1").Resize(UBound(a)).Value = b
End Sub
Click to expand...

Thank You DanteAmor
 
Upvote 0
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