Spellnumber function

tallboy

New Member
Joined
Mar 1, 2022
Messages
4
Office Version
  1. 365
  2. 2021
Help very new to VBA and using microsofts SpellNumber function getting a Compile error: Argument not optional
on this section highlighted in bold in the code

End Select

Result = Result & GetDigit _

(Right(TensText, 1)) ' Retrieve ones place.





VBA Code:
Option Explicit

'Main Function

Function SpellNumber(ByVal MyNumber)

Dim Pounds, Pence, Temp

Dim DecimalPlace, Count

ReDim Place(9) As String

Place(2) = " Thousand "

Place(3) = " Million "

Place(4) = " Billion "

Place(5) = " Trillion "

' String representation of amount.

MyNumber = Trim(Str(MyNumber))

' Position of decimal place 0 if none.

DecimalPlace = InStr(MyNumber, ".")

' Convert pence and set MyNumber to pound amount.

If DecimalPlace > 0 Then

Pence = GetTens(Left(Mid(MyNumber, DecimalPlace + 1) & _
"00", 2))

MyNumber = Trim(Left(MyNumber, DecimalPlace - 1))

End If

Count = 1

Do While MyNumber <> ""

Temp = GetHundreds(Right(MyNumber, 3))

If Temp <> "" Then Pounds = Temp & Place(Count) & Pounds

If Len(MyNumber) > 3 Then

MyNumber = Left(MyNumber, Len(MyNumber) - 3)

Else

MyNumber = ""

End If

Count = Count + 1

Loop

Select Case Pounds

Case ""

Pounds = "No Pounds"

Case "One"

Pounds = "One Pound"

Case Else

Pounds = Pounds & " Pounds"

End Select

Select Case Pence

Case ""

Pence = " and No Pence"

Case "One"

Pence = " and One Cent"

Case Else

Pence = " and " & Pence & " Pence"

End Select

SpellNumber = Pounds & Pence

End Function


' Converts a number from 100-999 into text

Function GetHundreds(ByVal MyNumber)

Dim Result As String

If Val(MyNumber) = 0 Then Exit Function

MyNumber = Right("000" & MyNumber, 3)

' Convert the hundreds place.

If Mid(MyNumber, 1, 1) <> "0" Then

Result = GetDigit(Mid(MyNumber, 1, 1)) & " Hundred "

End If

' Convert the tens and ones place.

If Mid(MyNumber, 2, 1) <> "0" Then

Result = Result & GetTens(Mid(MyNumber, 2))

Else

Result = Result & GetDigit(Mid(MyNumber, 3))

End If

GetHundreds = Result

End Function


' Converts a number from 10 to 99 into text.


Function GetTens(TensText)

Dim Result As String

Result = "" ' Null out the temporary function value.

If Val(Left(TensText, 1)) = 1 Then ' If value between 10-19...

Select Case Val(TensText)

Case 10: Result = "Ten"

Case 11: Result = "Eleven"

Case 12: Result = "Twelve"

Case 13: Result = "Thirteen"

Case 14: Result = "Fourteen"

Case 15: Result = "Fifteen"

Case 16: Result = "Sixteen"

Case 17: Result = "Seventeen"

Case 18: Result = "Eighteen"

Case 19: Result = "Nineteen"

Case Else

End Select

Else ' If value between 20-99...

Select Case Val(Left(TensText, 1))

Case 2: Result = "Twenty "

Case 3: Result = "Thirty "

Case 4: Result = "Forty "

Case 5: Result = "Fifty "

Case 6: Result = "Sixty "

Case 7: Result = "Seventy "

Case 8: Result = "Eighty "

Case 9: Result = "Ninety "

Case Else

End Select

Result = Result & GetDigit _

(Right(TensText, 1)) ' Retrieve ones place.

End If

GetTens = Result

End Function


' Converts a number from 1 to 9 into text.

Function GetDigit(Digit)

Select Case Val(Digit)

Case 1: GetDigit = "One"

Case 2: GetDigit = "Two"

Case 3: GetDigit = "Three"

Case 4: GetDigit = "Four"

Case 5: GetDigit = "Five"

Case 6: GetDigit = "Six"

Case 7: GetDigit = "Seven"

Case 8: GetDigit = "Eight"

Case 9: GetDigit = "Nine"

Case Else: GetDigit = ""

End Select

End Function
 

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Welcome to the Board!

I don't think it likes you splitting up the line in a middle of a function. You usually only split lines between arguments or pieces of a concatenation.

Try changing that problem line to this:
VBA Code:
Result = Result & GetDigit(Right(TensText, 1)) ' Retrieve ones place.
 
Upvote 0
Solution
You are welcome.
Glad I was able to help!
 
Upvote 0
Further issue just cropped up with this. when number is rounded up in the formulas result the text version as it only goes to 2 dp does not round up. is there a modification to the VBA code that can address this. working around at the moment using round down so number and text match.

£??,???.26 written as '... and twenty five pence' because the formula result is £??,???.258
 
Upvote 0
Are the values you are trying to run this against entered as numbers or strings?
 
Upvote 0
If yout want to round it to 2 decimal places, update this section of your SpellNumber function:
VBA Code:
' String representation of amount.
    MyNumber = Trim(Str(MyNumber))
with this:
VBA Code:
' String representation of amount.
    MyNumber = Round(MyNumber, 2)
    MyNumber = Trim(Str(MyNumber))
 
Upvote 0

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