Sort Variable Number of Rows Alphabetically -Copy Formula to Last Row -Last Row Issues

Rose401k

New Member
Joined
Aug 14, 2018
Messages
8
Hi Everyone,

In a formatting step of a larger macro, I am trying to select a variable number of rows beginning with cell C9:J, and then sort alphabetically. Below is what I have written, but it doesn't seem to be working so far (no errors given though).

Dim LRowC As Long
LRowC = Cells(Rows.Count, "C").End(xlUp).Row

Range("C9:J" & LRowC).Sort Key1:=Range("C9:C" & LRowC), _
Order1:=xlDescending, Header:=xlNo

Additionally I am trying to use a simliar process to copy vlookup formulas down column D next to all non-blank cells in column C. This is only working until about 5 rows down and I'm just stumped. Obviously I have something wrong in my understanding of the copy to last row coding here and I would really appreciate any corrected formulas/advice. Thanks!

Dim LRowD As Long
LRowD = Cells(Rows.Count, 1).End(xlUp).Row

ActiveCell.FormulaR1C1 = _
"=VLOOKUP(RC[-1],'MATC Positions'!R2C3:R4000C12,3,FALSE)"
Range("D9").Select
Selection.AutoFill Destination:=Range("D9:D" & LRowD)
 

Excel Facts

Return population for a City
If you have a list of cities in A2:A100, use Data, Geography. Then =A2.Population and copy down.
I believe that you only need the first cell in the column you want to sort by, so try this:
Code:
[COLOR=#333333]Range("C9:J" & LRowC).Sort Key1:=Range([/COLOR][COLOR=#ff0000][B]"C9"[/B][/COLOR][COLOR=#333333]), _[/COLOR]
[COLOR=#333333]Order1:=xlDescending, Header:=xlNo[/COLOR]

For your second part:
LRowD = Cells(Rows.Count, 1).End(xlUp).Row
This is actually finding the last row in column A. It is important to understand the format of Cells. It is Cells(row,column).
The column reference can be the letter or the number of the column. Column D would then be "D" or 4, i.e.
Code:
[COLOR=#333333]LRowD = Cells(Rows.Count, 4).End(xlUp).Row[/COLOR]
or
Code:
[COLOR=#333333]LRowD = Cells(Rows.Count, "D").End(xlUp).Row[/COLOR]
 
Last edited:
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