Sigmoidal Dose Response Curve

netchie

Board Regular
Joined
Sep 16, 2010
Messages
78
Hi,

Is there a way to create Sigmoidal Dose Response Curve using Excel? If yes, can you please let me know how to do this?

Thanks so much in advance.

netchie
 

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Do you have dose/response data that you're trying to fit to a sigmoidal curve, or something else?

There are (at least) two types of sigmoids used for this, an alebraic function and the logistics function. Do you know which one you want or need?
 
Upvote 0
Hi shg,
Here's the curve that I need:
http://www.graphpad.com/curvefit/introduction89.htm

It is a sigmoidal dose response curve. Non-linear regression. The shape of the curve is "S" shaped, and the inflection point is determined by regression analysis. It is called EC50- the theoretical x value which produces half-maximal response.<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p>

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</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in">
533<o:p></o:p>
</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in">
546<o:p></o:p>
</TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in">
654<o:p></o:p>
</TD></TR><TR style="HEIGHT: 15pt; mso-yfti-irow: 14; mso-yfti-lastrow: yes"><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD><TD style="BORDER-BOTTOM: #ece9d8; BORDER-LEFT: #ece9d8; PADDING-BOTTOM: 0in; BACKGROUND-COLOR: transparent; PADDING-LEFT: 0in; PADDING-RIGHT: 0in; HEIGHT: 15pt; BORDER-TOP: #ece9d8; BORDER-RIGHT: #ece9d8; PADDING-TOP: 0in"></TD></TR></TBODY></TABLE>
Is this posisble?

Thanks,
netchie
 
Upvote 0
Code:
       -B-- ---C---- ---D---- ----------------------------E-----------------------------
   2             Bot       0  D2: Input                                                 
   3             Top  20,512  D3: Input                                                 
   4               k  0.4786  D4: Input                                                 
   5              x0  2.1914  D5: Input                                                 
   6                                                                                    
   7        RMS Err    1,875  D7: {=SQRT(AVERAGE((D10:D22 - C10:C22)^2))}               
   8                                                                                    
   9    x      y       Fit                                                              
  10    4.0  21,120   18,051  D10 and down: =Bot + (Top-Bot) / (1 + 10 ^ (k*(x0 - B10)))
  11    3.5  13,207   16,589                                                            
  12    3.0  13,749   14,545                                                            
  13    2.5  10,342   11,983                                                            
  14    2.0  12,982    9,178                                                            
  15    1.5   7,315    6,528                                                            
  16    1.0   4,404    4,349                                                            
  17    0.5     596    2,754                                                            
  18    0.0     515    1,683                                                            
  19   -0.5     494    1,005                                                            
  20   -1.0     526      592                                                            
  21   -1.5     508      345                                                            
  22   -2.0     533      200

Data > Solver, set D7 to minimum by changing D2:D5 with the constraint that D2 >= 0.

I set D2:D5 initially to 1.

(x0 is EC50)
 
Last edited:
Upvote 0
Wow! You replied so fast.

I'll do this now and will let you know the outcome.

Thanks so much for your help. I really apprecite it.

netchie.
 
Last edited:
Upvote 0
Ugh! I really thought it's easy but it's not. I technically copy exactly what you've posted and I was like "What then"? LOL. Ugh!

I'm not good in Excel and this is new to me. Can you please explain it to me? I literally put the value to each cell. It didn't change to a graph lol.

When you said D3: Input, what is that mean? When you say D7: {=SQRT(AVERAGE((D10:D22 - C10:C22)^2))} is this mean I will put it all to D7 cell? Did you just type the value on D or you created a formula? I tried to put
=Bot + (Top-Bot) / (1 + 10 ^ (k*(x0 - B10)))<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p>


from D2 to D22 but it says "#NAME?".

http://i255.photobucket.com/albums/hh122/barkda-13/StupidMe.jpg
 
Upvote 0
Bot, Top, x0, and k are named ranges. To create them, select C2:D5 and do

Formula > Defined Names > Create from Selection, and tick Left Column.

D7 is an array formula. Paste

=SQRT(AVERAGE((D10:D22 - C10:C22)^2))

... into the formula bar, and instead of pressing Enter, press and hold the Ctrl and Shift keys, then press Enter. That will make the curly braces appear; you can't type them in.

EDIT: If you're going to use my formulas, you need to use the same cells. Yours are all shifted over a column.
 
Last edited:
Upvote 0
Hi shg,

I hope your patience is super long on me. Never seen this curve before and how to do this.

Questions:

1. You said Bot, Top, x0, and k are named ranges. To create them, select C2:D5 and do Formula > Defined Names > Create from Selection, and tick Left Column. -

I did highlight C2 to D5, went to Formula, Create from Selection, and tick Left Column and then I clicked OK. After that, is this mean I will start typing "Bot" to D2, "Top" to D3, "k" to D4, and x0" to D5 manually?


2. D2 to D7 values - are all those you just typed manually?

3. D10 and down: =Bot + (Top-Bot) / (1 + 10 ^ (k*(x0 - B10)))

Are those from D10-D22 (Fit) values are came from the formula you've listed --> above

EDIT - I used the formula for E10 and the answer is 20508.2 and not 18,051.


4. So let's pretend I get all of these correctly (I super hope so), then which ranges I should highlight to get a graph that I need? From C9-E22?
 
Last edited:
Upvote 0
1. It means you can use those names in formulas instead of using cell references. If you're more comfortable with cell references, use those instead.

2. D2:D5 were initially set to random values (1) by me, and then changed by Solver. D6 is not used. D7 is the array formula previously described.

3. The formula just uses the named ranges previously created.

4. B10:C22 are your measured dose/response data; plot using markers only. D10:D22 is the logistics curve of best fit; plot as a smooth line only (no markers) and observe the fit to the data points.
 
Upvote 0

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