Searching an array of cells for a value and returning the column headers where a value exists

Mattyastill

New Member
Joined
Nov 27, 2017
Messages
23
Hi,

I'm trying to find a way which i can return the column headers where a value exists in the cells F:M for the same row. As you can see from the screenshot for the first row, i would like to search for any value in row 3 and bring back the column heads for the rows. I have shown in Column N of what i would like to return if there is a value there.

I have tried a combination of Index, Match Index, Max and Index, Sum-product but just cant seem to get it working.

1576156578052.png



Any help would be much appreciated

Thanks,

Matthew
 

Excel Facts

Which came first: VisiCalc or Lotus 1-2-3?
Dan Bricklin and Bob Frankston debuted VisiCalc in 1979 as a Visible Calculator. Lotus 1-2-3 debuted in the early 1980's, from Mitch Kapor.
What version of Xl are you using?
 
Upvote 0
In that case try
=TEXTJOIN(", ",1,IF(F3:M3<>"",F2:M2,""))

This will need array entry, Ctrl Shift Enter, unless you have the new Dynamic Array Functions
 
Upvote 0
In that case try
=TEXTJOIN(", ",1,IF(F3:M3<>"",F2:M2,""))

This will need array entry, Ctrl Shift Enter, unless you have the new Dynamic Array Functions

Ahhh yes that works perfectly thanks so much, only issue is in some of my columns further down in the data there are 0's rather than all being blank. Could there be additional criteria added to this so it ignores blanks and 0's?
 
Upvote 0
How about
=TEXTJOIN(", ",1,IF((F3:M3<>"")*(F3:M3<>0),F2:M2,""))
 
Upvote 0
You're welcome & thanks for the feedback
 
Upvote 0

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