Run-time error 462

Pucci1150

New Member
Joined
Feb 19, 2024
Messages
3
Office Version
  1. 365
Platform
  1. Windows
Hi all,

I'm trying to automate the filling of a word template contract and I keep getting the 462 run-time error. The debug gives me the error colored in red below. I'm hoping for some directions on how to correct my code. I've tried couple of things already but nothing seems to be working. Could the problem be linked to authorisation problems ? The template is on a OneDrive but the authorizations should be fine.

Thanks in advance,:)

Rich (BB code):
Sub RemplirContrat()
    Dim appWord As Object
    Dim doc As Object
    Dim contratTemplate As String

    contratTemplate = "C:\Users\...."

    Set appWord = CreateObject("Word.Application")
    appWord.Visible = True
   
    Set doc = appWord.Documents.Open(contratTemplate)

    If Not doc.ReadOnly Then
        doc.Content.Select
        appWord.Selection.Copy

        Set doc = appWord.Documents.Add
        doc.Range.Paste
    End If

    With doc.Content.Find
        .Execute FindText:="<<Date entrée en vigueur>>", ReplaceWith:=Cells(2, 1).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Nom Société>>", ReplaceWith:=Cells(2, 2).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Adresse>>", ReplaceWith:=Cells(2, 3).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Numéro Entreprise>>", ReplaceWith:=Cells(2, 4).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Représentant>>", ReplaceWith:=Cells(2, 5).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Fonction>>", ReplaceWith:=Cells(2, 6).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<<<% dispense>>", ReplaceWith:=Cells(2, 7).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Titre Client>>", ReplaceWith:=Cells(2, 8).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Forme Sociale>>", ReplaceWith:=Cells(2, 9).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Place de signature>>", ReplaceWith:=Cells(2, 10).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<Date du jour>>", ReplaceWith:=Cells(2, 11).Value, Replace:=wdReplaceAll
        .Execute FindText:="<<DPO ou Personne de contact>>", ReplaceWith:=Cells(2, 12).Value, Replace:=wdReplaceAll
    End With

    doc.SaveAs "C:\..."

    appWord.Documents(contratTemplate).Close False

    appWord.Quit
    Set doc = Nothing
    Set appWord = Nothing
End Sub
 
Last edited by a moderator:

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Do you have a reference set to the Word object library? I assume not since your code is late bound, which means that you cannot use constants from that library (e.g. wdReplaceAll) without declaring them yourself.

It's also odd to reuse an object variable for another object in the same code.
 
Upvote 0
To be totally honest i'm very unexperienced with VBA and i've mainly been reusing codes i found online so far, and I have not set any references in the word object library.
 
Upvote 0
Try adding this to the top of your code:

Code:
   Const wdReplaceAll As Long = 2

then save the workbook and restart Excel before trying it again (which should allow any hidden Word instances to close)
 
Upvote 0
I did it and i'm still receiving the same error message (run-time error 462). I've tried to look into the references as you mentionned just before but i cannot select it in the Tools section of VBA.
 
Upvote 0
I did it and i'm still receiving the same error message (run-time error 462). I've tried to look into the references as you mentionned just before but i cannot select it in the Tools section of VBA.
Pul, did you ever resolve this? I am having a similar problem.
 
Upvote 0
Duplicate to: Run Time Error 462

@CPO_Rick,
In future, please do not post the same question multiple times. Per Forum Rules (#12), posts of a duplicate nature will typically be locked or deleted.

Anyone answering CPO_Rick's question, please post to the other thread linked at the top of this post.
 
Upvote 0
Duplicate to: Run Time Error 462

@CPO_Rick,
In future, please do not post the same question multiple times. Per Forum Rules (#12), posts of a duplicate nature will typically be locked or deleted.

Anyone answering CPO_Rick's question, please post to the other thread linked at the top of this post.
Sorry, I don't even know how I did that. It was unintentional.
 
Upvote 0

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