Hi
I would appreciate if anybody could answer this small question: In Solver, If a I have a cell whose value is set to be binary, + the cell is also a changing cell, Do I need to set the value equal to 1, before running the Solver?
Example:
Set C3 = 0 <--- this is my x variable, set to be Integer, and a Changing Cell in Solver
Set C4 = 0 <--- this is my y variable, set to be Binary, and a Changing Cell
Constraint: C6=2*x*y <= 11
Target Cell: Maximizing C8: = C3*C4
Why is it that if C4=0 before running the Solver it gives me 0's in all cells after running it, but if C4=1 it actually does succeed to solve the problem (giving me x=5)? Surely when C4 is set as Changing Cell it should still find the solution!!
I would appreciate if anybody could answer this small question: In Solver, If a I have a cell whose value is set to be binary, + the cell is also a changing cell, Do I need to set the value equal to 1, before running the Solver?
Example:
Set C3 = 0 <--- this is my x variable, set to be Integer, and a Changing Cell in Solver
Set C4 = 0 <--- this is my y variable, set to be Binary, and a Changing Cell
Constraint: C6=2*x*y <= 11
Target Cell: Maximizing C8: = C3*C4
Why is it that if C4=0 before running the Solver it gives me 0's in all cells after running it, but if C4=1 it actually does succeed to solve the problem (giving me x=5)? Surely when C4 is set as Changing Cell it should still find the solution!!
Last edited: