Relative referencing with structured table references

samjsteffes

New Member
Joined
Feb 27, 2018
Messages
16
Hi all,

While writing out the title for this posting, it occurred to me how much it sounds like an oxymoron... but I am going to go ahead and post anyway in search of an answer.

I have a ListObject (table) that contains two columns like the sample below...

[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD]Footage[/TD]
[TD]Length[/TD]
[/TR]
[TR]
[TD]0[/TD]
[TD]=100 - 0[/TD]
[/TR]
[TR]
[TD]100[/TD]
[TD]=150 - 100[/TD]
[/TR]
[TR]
[TD]150[/TD]
[TD]=275 - 150[/TD]
[/TR]
[TR]
[TD]275[/TD]
[TD]=415 - 275[/TD]
[/TR]
[TR]
[TD]415[/TD]
[TD]left blank[/TD]
[/TR]
</tbody>[/TABLE]

I want to populate the "length" column with the calculated distance between the consecutive footage values to the left, and left+down from its position. I recorded a macro while setting this formula, which resulted in the following expression:

"=R[1]C[-1]-[@[Footage]]"

This formula works fine, as does "=R[1]C[-1]-R[0]C[-1]" which uses strictly relative referencing. However, I am curious if there is someway of using the [@[Footage]] syntax for both cell references. This way, I could still perform this calculation if another column was to be inserted between these two, and it was no longer directly adjacent.

Is there anyway to do this? Such as "=([@[Footage]].offset(1) - [@[Footage]]". I'm sure that is not correct syntax, but I just want to drive home the point that I want the "Footage" value offset by one row from the current position.

Here is the exact code I am using to set the formula for the "length" column

Code:
tbl.DataBodyRange(1, a).FormulaR1C1 = "=R[1]C[-1]-[@[Section Start]]"

note: I indexed the position of the length column to the variable "a". Since its a table, inserting the formula to the first row extends the formula to the entire column.

Thanks,
sjs
 

Excel Facts

VLOOKUP to Left?
Use =VLOOKUP(A2,CHOOSE({1,2},$Z$1:$Z$99,$Y$1:$Y$99),2,False) to lookup Y values to left of Z values.
Hi Sam

With a table like the one in the example, try:

Code:
Sub Test()
Dim lstObj As ListObject

Set lstObj = ActiveSheet.ListObjects("Table1")

lstObj.ListColumns("Length").DataBodyRange(1).Formula = _
    "=IFERROR(INDEX([Footage],ROW()-MIN(ROW([Footage]))+2)-[@Footage],"""")"

End Sub
 
Upvote 0

Forum statistics

Threads
1,223,227
Messages
6,170,849
Members
452,361
Latest member
d3ad3y3

We've detected that you are using an adblocker.

We have a great community of people providing Excel help here, but the hosting costs are enormous. You can help keep this site running by allowing ads on MrExcel.com.
Allow Ads at MrExcel

Which adblocker are you using?

Disable AdBlock

Follow these easy steps to disable AdBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the icon in the browser’s toolbar.
2)Click on the "Pause on this site" option.
Go back

Disable AdBlock Plus

Follow these easy steps to disable AdBlock Plus

1)Click on the icon in the browser’s toolbar.
2)Click on the toggle to disable it for "mrexcel.com".
Go back

Disable uBlock Origin

Follow these easy steps to disable uBlock Origin

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back

Disable uBlock

Follow these easy steps to disable uBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back
Back
Top