Regular Expression for comparing words

svelma

New Member
Joined
Aug 2, 2011
Messages
14
Can somebody give me a regular expression to do an approximate, atleast 3 letter match between two words.

For example I have "Alex Mike" in one column and "mAlex" in another. There is a space in between Alex and Mike and we are comparing to mAlex. I think its tricky.

I tried using the following expressions:
[\w]*
[\w]{3,}?
[a-zA-Z]*
etc,
But I still don't find a match between some of the records. I have over 4000 records and I am trying to use Regex in demand tools with salesforce.

There is a fuzzy option in demand tools that avoids spaces. So, I even tried using that, but my regular expression needs some correction.
Please help me out.
Thanks,
Velma
 

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I doubt if I have an option to use code in demand tools. But I can certainly try in excel.

If I am not wrong, do you mean a macro when you say code?
 
Upvote 0
Sorry, yes I did mean an Excel macro. I'm not familiar with Regex. Would an Excel macro work for your situation?
 
Upvote 0
Why not take the lowercase of the first letter of the second word and append it to proper case of the first word and compare to that?

Alex Mike = mAlex
 
Upvote 0
Code:
Sub test()
Dim c As Range, strTest, t
For Each c In Range("A1:A" & Range("A" & Rows.Count).End(xlUp).Row)
    t = Split(c)
    strTest = LCase(Left(t(0), 1)) & StrConv(t(1), vbProperCase)
    If c.Offset(, 1) = strTest Then c.Offset(, 2) = "MATCH"
Next
End Sub
 
Upvote 0
@HOTPEPPER: There are 4000 records and not every record is in the same format. I mean, both my columns may have either one or two words, small or caps. But these are the same names in different format(full name or alias or user name etc). So, I wanted to sort the records that atleast have 3 successive letters matching.
Sorry if this is confusing.

In short, I want to match column A with column B and sort those that have same 3 or more successive letters.

Examples of my data:
ColumnA----------Column B
BasakSomaya-------LEVIN SOMAYA
AndrewCochrane----ACOCHRANE
Alexandra Mininger--AlexMininger
AnnaKrasniewska---akrasniewska
AlexRoss-----------ZROSS
CarstenSchmidt-----PJ Jauhari
.
.
.
etc

@craig.penny: Sure a macro can be helpful, even though I never used it I will definitely try, if I have no other option. But an excel formula would be of great help.

Thank you guys.
-Velma.
 
Upvote 0
This is how I would do it, though surely there are better approaches.

Open the VBA editor by pressing Alt-F11 then paste in this code.

Code:
Sub CompareText()
Dim i As Integer
Dim iRow As Integer
For iRow = 1 To 4000
      For i = 1 To Len(Cells(iRow, 1)) - 2
            If InStr(1, Cells(iRow, 2).Value, Mid(Cells(iRow, 1), i, 3), vbTextCompare) > 0 Then
                  Cells(iRow, 3) = "Match Found"
            End If
      Next i
Next iRow
End Sub

With the cursor positioned somewhere within the block of code listed above, press F5 to run it.

Let me know how/if it works for you. Don't hesitate to ask for more help. If you're unfamiliar with the VBA editor it can be confusing!
 
Upvote 0
Here's a UDF that generates the following results:

Code:
      --------A--------- -----B------ -----C------ -----------D------------
  1   BasakSomaya        LEVIN SOMAYA Somaya       C1 and down: =LCS(A1,B1)
  2   AndrewCochrane     ACOCHRANE    COCHRANE                             
  3   Alexandra Mininger AlexMininger Mininger                             
  4   AnnaKrasniewska    akrasniewska akrasniewska                         
  5   AlexRoss           ZROSS        ROSS                                 
  6   CarstenSchmidt     PJ Jauhari   ar

Code:
Function LCS(ByVal s1 As String, ByVal s2 As String, _
                      Optional bCaseSensitive = False) As String
    ' Returns the Longest Common Substring in s1 and s2
    ' shg 2009
 
    ' Max steps = Len(shorter) * (Len(shorter) + 1) / 2
 
    Dim iComp       As VbCompareMethod
    Dim iLen        As Long     ' match length
    Dim iBeg        As Long     ' where match begins in s1
    Dim sT          As String   ' temp string for swapping
 
    iComp = IIf(bCaseSensitive, VBA.vbBinaryCompare, VBA.vbTextCompare)
 
    ' swap if necessary so s1 is the longer string
    If Len(s1) < Len(s2) Then: sT = s1: s1 = s2: s2 = sT
 
    For iLen = Len(s2) To 1 Step -1
        For iBeg = 1 To Len(s2) - iLen + 1
            LCS = Mid(s2, iBeg, iLen)
            If InStr(1, s1, LCS, iComp) Then Exit Function
        Next iBeg
    Next iLen
    LCS = vbNullString
End Function
 
Upvote 0
@Craig.Penny: That was awesome dude. It worked like a charm. Thank you.

@Shg: I tried to do the same thing what Craig suggested with you function, but it didn't work. Do I need to add something to it?
 
Upvote 0

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