Reference horizontal data vertically and in sets of 3

duranimal86

New Member
Joined
Jul 24, 2019
Messages
18
Office Version
  1. 365
Platform
  1. Windows
Hello, I am trying to find a way to reference rows of horizontal data with a formula to pull different columns in sets of 3 rows for each row of data. So each row of data would result in 3 corresponding formula rows with different columns referenced in each of the 3 rows. Then i would like to be able to have that set of 3 pattern copy down for multiple rows of horizontal data. I have been trying to make something work with INDEX and/or OFFSET, but haven't been able to get it to work. Below is example data to try and illustrate what i am looking for.

Horizontal Data to be referenced:
ID11A1B1C1D1E1F
ID22A2B2C2D2E2F
ID33A3B3C3D3E3F
ID44A4B4C4D4E4F


The result I am looking for:
ID11A(hardkeyed1)(hardkeyed2)1D
ID11A1B1C1E
ID11A1B1C1F
ID22A(hardkeyed1)(hardkeyed2)2D
ID22A2B2C2E
ID22A2B2C2F
ID33A(hardkeyed1)(hardkeyed2)3D
ID33A3B3C3E
ID33A3B3C3F
ID44A(hardkeyed1)(hardkeyed2)4D
ID44A4B4C4E
ID44A4B4C4F
 

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I'm not exactly sure what the 'hardkeyed' cells are but perhaps you would be manually typing over the "?' results below?

21 07 14.xlsm
ABCDEFG
1ID11A1B1C1D1E1F
2ID22A2B2C2D2E2F
3ID33A3B3C3D3E3F
4ID44A4B4C4D4E4F
5
6ID11A??1D 
7ID11A1B1C 1E
8ID11A1B1C 1F
9ID22A??2D 
10ID22A2B2C 2E
11ID22A2B2C 2F
12ID33A??3D 
13ID33A3B3C 3E
14ID33A3B3C 3F
15ID44A??4D 
16ID44A4B4C 4E
17ID44A4B4C 4F
duranimal86
Cell Formulas
RangeFormula
A6:B17A6=INDEX(A$1:A$4,INT((ROWS(A$6:A6)+2)/3))
C6:D17C6=IF(MOD(ROWS(C$6:C6),3)=1,"?",INDEX(C$1:C$4,INT((ROWS(C$6:C6)+2)/3)))
E6:E17E6=IF(MOD(ROWS(E$6:E6),3)=1,INDEX(E$1:E$4,INT((ROWS(E$6:E6)+2)/3)),"")
F6:F17F6=IF(MOD(ROWS(F$6:F6),3)=1,"",INDEX(F$1:G$4,INT((ROWS(F$6:F6)+2)/3),1+(MOD(ROWS(F$6:F6),3)=0)))
 
Upvote 0
Solution
Wow, that worked perfectly! The "hardkeyed" were for constant numbers that will always be the same, so i was able to enter those in place of the "?" to get exactly what i needed. Thank you!
 
Upvote 0

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