Recalculating Data Unit values

ldoodle

New Member
Joined
Mar 2, 2010
Messages
40
Office Version
  1. 365
Platform
  1. Windows
Hey,

Let's say I have this:

Excel Formula:
A1: 10GB
B1: =CONVERT(A1,"Gibyte","byte")

That will give me the exact byte value of 10GB. However, I want to step up to next "whole" byte; "whole" will depend on the unit in A1:

Excel Formula:
A1: 640.5
B1: =CONVERT(A1,"Gibyte","byte")

Excel Formula:
A1: 10.5GB
B1: =CONVERT(A1,"Gibyte","byte")

That will give me 800.5MB and 10.5GB in byte value, but I'd want those to be stepped up to 641GB and 11GB (possibly even 642GB and 12GB to avoid odd number) in byte notation. However it's not as simple as rounding to 1 decimal, since this one is allowable:

Excel Formula:
A1: 1.5TB
B1: =CONVERT(A1,"Tibyte","byte")

But this one isn't:

Excel Formula:
A1: 1.57TB
B1: =CONVERT(A1,"Tibyte","byte")

That should be rounded to 1.6TB in bytes.

This is for VM sizing, e.g. you'd never spec a VM RAM with decimals in (10.5GB) but you would give it 1.5TB. Out of interest I am obviously going based on 1024 (binary) instead of 1000 (decimal). Not sure whether this is the correct way or not. Some Hypervisors still require MB notation for RAM, e.g. 10240MB for 10GB.

(I'm being cleverer than shown in the CONVERT function to actually determine the source format (B, KB, MB, GB, TB, PB, EB, ZB, YB).)

Thanks
 

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Thanks. That seems OK for GB, but for TB it rounds to next whole number.

55.5GB becomes 56GB = good
1.5TB becomes 2TB = not good
You can use a modified version of this formula for TB
B1: = CONVERT(INT(A1*10 + 0.9)/10, "Tibyte","byte") in your formula

However, if you provide the code for your CONVERT function the "rounding" calculation could be part of that formula, or maybe there is a better solution than what I have provided.

Samples of your unconverted data would be very helpful as well.
 
Upvote 0
You can use a modified version of this formula for TB
B1: = CONVERT(INT(A1*10 + 0.9)/10, "Tibyte","byte") in your formula

However, if you provide the code for your CONVERT function the "rounding" calculation could be part of that formula, or maybe there is a better solution than what I have provided.

Samples of your unconverted data would be very helpful as well.
Here is a sample of another way to do your conversion and format of the Memory values. All of the columns would not be necessary. I include them so you could, hopefully, see how I did the conversion.

Book3
ABCD
3RAMMIN RAM BYTES10^(n*3) DIVISORCONVERTED
410102411.0 KB
5100102411.0 KB
61000102411.0 KB
72000204812.0 KB
81000010240110.2 KB
91500015360115.4 KB
101000001003521100.4 KB
112000002007041200.7 KB
129000009000961900.1 KB
135000005007361500.7 KB
141000000100044821.0 MB
152000000200089622.0 MB
168000000800051228.0 MB
179000005900096029.0 MB
181000000010000384210.0 MB
195000000050000896250.0 MB
209000000090000384290.0 MB
211000000001000007682100.0 MB
225000000005000007682500.0 MB
239000000009000007682900.0 MB
241000000000100000051231.0 GB
257000000000700000051237.0 GB
269000000000900000051239.0 GB
271000000000010000000000310.0 GB
289000000000090000000000390.0 GB
291E+111E+113100.0 GB
309E+119E+113900.0 GB
311E+121E+1241.0 TB
329E+129E+1249.0 TB
Sheet6
Cell Formulas
RangeFormula
B4:B32B4=INT((A4+1023)/1024)*1024
C4:C32C4=INT(INT(LOG10(B4))/3)
D4:D32D4=TEXT(B4/(10^(C4*3)),"0.0 ") & CHOOSE(C4,"KB","MB","GB","TB")
 
Upvote 0

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