ranking with tie-breaker criteria based on larger or smaller value

valmir

Active Member
Joined
Feb 10, 2021
Messages
267
Office Version
  1. 365
Platform
  1. Windows
Hello everyone
I am using this formula:
=RANK.EQ(J1;$J$1:$J$16)+COUNTIF($J$1:J1;J1)-1
to rank a classification table however, in case of a tie, I want the row with the larger value in column I to rank higher. In this particular example, row 4 should be ranked above row 3 because row 4 has a higher value in column I than row 3. Same problem between rows 11 and 12 and from rows 13 to 16. I have added the current status and the desired outcome. Also, I would like to how it is in case I have to rank with the second criteria based on smaller value in column I). Thanks

Book1
ABCDEFGHIJKLMNOPQRSTU
11PET3300112+991PET3300112+99
22PRO321031+272PRO321031+27
33MAQ320143+163PRI220030+36
44PRI220030+364MAQ320143+16
55CAA312062+455CAA312062+45
66FER312043+156FER312043+15
77INT311133047INT31113304
88SAG311122048SAG31112204
99DES303044039DES30304403
1010ACA302112-1210ACA302112-12
1111CCU302135-2211SRC302112-12
1212SRC302112-1212CCU302135-22
1313BAI301219-8113WIL201112-11
1414LIB301215-4114SCC301203-31
1515SCC301203-3115LIB301215-41
1616WIL201112-1116BAI301219-81
Sheet1
 

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=RANK.EQ(J1;$J$1:$J$16)+COUNTIFS($J$1:J1;J1; $I$1:I1;"<"&I1)
After applying your formula this is what I am getting. Not only it has no effect but it is also giving me some blanks. Am I doing something wrong?

Book1
ABCDEFGHI
1PET3300112+99
2PRO321031+27
3MAQ320143+16
4PRI220030+36
5CAA312062+45
6
7INT31113304
8
9DES30304403
10ACA302112-12
11SRC302112-12
12
13BAI301219-81
14LIB301215-41
15SCC301203-31
16WIL201112-11
Sheet1
 
Upvote 0
Maybe like this:

=RANK.EQ(J1,$J$1:$J$16)+COUNTIFS($J$1:$J$16,J1, $I$1:$I$16,">"&I1)
 
Upvote 0
Maybe like this:

=RANK.EQ(J1,$J$1:$J$16)+COUNTIFS($J$1:$J$16,J1, $I$1:$I$16,">"&I1)
With this one this is the result. Still not good
Book1
ABCDEFGHI
1
2PET3300112+99
3
4PRI220030+36
5MAQ320143+16
6
7CAA312062+45
8
9DES30304403
10ACA302112-12
11
12
13BAI301219-81
14WIL201112-11
15
16
Sheet1
 
Upvote 0
Book1
ABCDEFGHIJK
11PET3300112991
22PRO321031272
33MAQ320143164
44PRI220030363
55CAA312062455
66FER312043156
77INT311133047
88SAG311122047
99DES303044039
1010ACA302112-1210
1111CCU302135-2212
1212SRC302112-1210
1313BAI301219-8116
1414LIB301215-4115
1515SCC301203-3114
1616WIL201112-1113
Sheet1
Cell Formulas
RangeFormula
K1:K16K1=RANK.EQ(J1,$J$1:$J$16)+COUNTIFS($J$1:$J$16,J1, $I$1:$I$16,">"&I1)
 
Upvote 0
Solution
=RANK.EQ(J1,$J$1:$J$16)+COUNTIFS($J$1:$J$16,J1, $I$1:$I$16,">"&I1)
Can you please tell me which index match are you using to get that? Probably has to do with the one I am using?
=IFERROR(INDEX($B$1:$J$16;MATCH(A1;$K$1:$K$16;0);1);"") to =IFERROR(INDEX($B$1:$J$16;MATCH(A1;$K$1:$K$16;0);9);"")
 
Upvote 0
Can you please tell me which index match are you using to get that? Probably has to do with the one I am using?
=IFERROR(INDEX($B$1:$J$16;MATCH(A1;$K$1:$K$16;0);1);"") to =IFERROR(INDEX($B$1:$J$16;MATCH(A1;$K$1:$K$16;0);9);"")
 
Upvote 0
Thanks for the help even though I am stuck with blank rows because the index match formula I am using only shows one value whenever there are two exact maches but I know that it is not your fault. Your formula works perfectly. Thanks again!
 
Upvote 0

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