Random number 1 - x

CaptBrownShoes

New Member
Joined
May 16, 2024
Messages
5
Office Version
  1. 2021
Platform
  1. Windows
1715892762344.png

Here is the situation:
The table above is needing a random number that does not duplicate based on the remaining cards in deck.
The correct answer would work as follows:
  • RAND column looks at Discard Pile and if = "a" (webdings check), then "". Done!
  • Then the RAND column would look at the number of remaining cards "12" in Odds Total column as the max random number. Done!
  • Then the RAND column picks a number from 1 - 12 that does not exist in the previous attempts. NOPE!!! Can't figure this one out.
=IF([@[Discard Pile a]]="a","",RANDBETWEEN(1,tblExCards[[#Totals],[Odds]]))

I cannot get that to happen. Any suggestions?

Thus, is the a need for a VBA statement?

Thank you Team!
 

Excel Facts

Back into an answer in Excel
Use Data, What-If Analysis, Goal Seek to find the correct input cell value to reach a desired result
Try:
Book1
ABC
1OddsDiscard PileRand
28.30%9
3
48.30%7
5
68.30%10
78.30%8
8
98.30%12
10
118.30%11
12
138.30%2
14
158.30%4
168.30%6
17
188.30%5
19
2016.70%3
2116.70%1
22128
Sheet4
Cell Formulas
RangeFormula
C2:C21C2=LET( m,MAP(B2:B21,LAMBDA(m,COUNTIFS(INDEX(B2:B21,1):m,""))), IF(B2:B21="",INDEX(SORTBY(SEQUENCE(A22),RANDARRAY(A22)),IF(B2:B21="",m)),""))
A22A22=COUNTBLANK(B2:B21)
Dynamic array formulas.
 
Last edited:
Upvote 0
A little shorter.
Excel Formula:
=IF(B2:B21="",INDEX(SORTBY(SEQUENCE(A22),RANDARRAY(A22)),MAP(B2:B21,LAMBDA(m,COUNTIFS(INDEX(B2:B21,1):m,"")))),"")
 
Upvote 0
Or try this:

Book1
ABC
1OddsDiscard PileRand
20.0831
3 
40.0839
5 
60.0832
70.08310
8 
90.0837
10 
110.08311
12 
130.0833
14 
150.08312
160.0834
17 
180.0838
19 
200.1675
210.1676
2212
Sheet1
Cell Formulas
RangeFormula
C2:C21C2=IF(B2="",AGGREGATE(15,6,SEQUENCE($A$22)/(COUNTIFS($C$1:C1,SEQUENCE($A$22))=0),RANDBETWEEN(1,$A$22-COUNT($C$1:C1))),"")
A22A22=COUNT(A2:A21)
 
Upvote 0
Solution
Or try this:

Book1
ABC
1OddsDiscard PileRand
20.0831
3 
40.0839
5 
60.0832
70.08310
8 
90.0837
10 
110.08311
12 
130.0833
14 
150.08312
160.0834
17 
180.0838
19 
200.1675
210.1676
2212
Sheet1
Cell Formulas
RangeFormula
C2:C21C2=IF(B2="",AGGREGATE(15,6,SEQUENCE($A$22)/(COUNTIFS($C$1:C1,SEQUENCE($A$22))=0),RANDBETWEEN(1,$A$22-COUNT($C$1:C1))),"")
A22A22=COUNT(A2:A21)
Thank you!!!! Worked SWIMMINGLY!!!
 
Upvote 0

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