Problem infinite loop - find and bold based on cell value

jptaz

New Member
Joined
May 1, 2020
Messages
46
Office Version
  1. 2010
Platform
  1. Windows
Hello,

I have found this code to find and bold specific words in my excel worksheet. The code works good with the 9 first words, however, if I add words based on cell value (text 10 and 11), the code seems to run endlessly and ultimately crashes. The line here seems to be the problem if I debug it " rCell.Characters(iSeek, Len(sToFind)).Font.bold = True". I'm really no expert and I hope someone can help me with this :)

thank you


VBA Code:
Sub Find_and_Bold1HAP() 

Dim rCell As Range, sToFind As String, iSeek As Long
Dim Text(1 To 11) As String
Dim i As Integer
Dim ws As Worksheet
 
 Set ws = Worksheets("Rapport ini")

Text(1) = "DOSSIER : "
Text(2) = "NOM, PRÉNOM :"
Text(3) = "DATE DE NAISSANCE :"
Text(4) = "Programme :"
Text(5) = "ÂGE :"
Text(6) = "SEXE :"
Text(7) = "TÉLÉPHONE :"
Text(8) = "ADRESSE :"
Text(9) = "Commentaires :"
Text(10) = Worksheets("Données").Range("D211").Text
Text(11) = Worksheets("Données").Range("E211").Text


For i = LBound(Text) To UBound(Text)
    For Each rCell In ws.Range("A1:S10, A54, A69, A72, A91")
    
            sToFind = Text(i)
            iSeek = InStr(1, rCell.Value, sToFind)
        Do While iSeek > 0
         
            rCell.Characters(iSeek, Len(sToFind)).Font.bold = True
            iSeek = InStr(iSeek + 1, rCell.Value, sToFind)
         Loop
    Next rCell
Next i
 
End Sub
 

Excel Facts

Format cells as time
Select range and press Ctrl+Shift+2 to format cells as time. (Shift 2 is the @ sign).
You do not need the inner Do loop. InStr will find the string anywhere, you do not have to check each character. The first argument is optional and just tells it where to start looking. Leave it out, and it will always start at the beginning.

VBA Code:
   For i = LBound(Text) To UBound(Text)
       For Each rCell In ws.Range("A1:S10, A54, A69, A72, A91")
      
         sToFind = Text(i)
         iSeek = InStr(rCell.Value, sToFind)
         If iSeek > 0 Then
            rCell.Characters(iSeek, Len(sToFind)).Font.Bold = True
         End If
        
       Next rCell
   Next i
 
Upvote 0
Solution
You do not need the inner Do loop. InStr will find the string anywhere, you do not have to check each character. The first argument is optional and just tells it where to start looking. Leave it out, and it will always start at the beginning.

VBA Code:
   For i = LBound(Text) To UBound(Text)
       For Each rCell In ws.Range("A1:S10, A54, A69, A72, A91")
     
         sToFind = Text(i)
         iSeek = InStr(rCell.Value, sToFind)
         If iSeek > 0 Then
            rCell.Characters(iSeek, Len(sToFind)).Font.Bold = True
         End If
       
       Next rCell
   Next i
Thank you very much, it works great!

Have a nice day!!
 
Upvote 0

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