Power Query Custom Column to count number of instances - multiple criteria

[tbablue]

Hi Forum,

I have a table called 'Output' - the table has just five (5) fields; Index, Checker, Title, Manager ID, Role Type.

I want to introduce a custom column in Power Query that will count the number of entries that are matched in 'Checker', 'Title', and 'Manager ID'.

Most grateful for any assistance.

 

[tbablue]

I used a combination of GROUP & INDEX Column to do this.

This was the solution that I found.

 

[smozgur]

Thanks for posting your solution. The video explains how to group data for aggregation.
So you could mark your own answer post as the solution.

Additionally, to help future readers and make this question more useful, here is how it is done in words.
Select Checker, Title, and Manager ID columns, right-click on the headers, and Group By, then select Count for the operation.

The following is the M code for the same scenario:

let
    Source = Excel.CurrentWorkbook(){[Name = "Table1"]}[Content],
    GroupRows = Table.Group(Source, {"Checker", "Title", "Manager ID"}, {{"Count", each Table.RowCount(_)}})
 in
    GroupRows

 

[tbablue]

Thanks for posting your solution. The video explains how to group data for aggregation.
So you could mark your own answer post as the solution.

Additionally, to help future readers and make this question more useful, here is how it is done in words.
Select Checker, Title, and Manager ID columns, right-click on the headers, and Group By, then select Count for the operation.

View attachment 93347

View attachment 93348


The following is the M code for the same scenario:

let
    Source = Excel.CurrentWorkbook(){[Name = "Table1"]}[Content],
    GroupRows = Table.Group(Source, {"Checker", "Title", "Manager ID"}, {{"Count", each Table.RowCount(_)}})
 in
    GroupRows

Thank you for taking the time to respond. I know that some members don't show the appreciation that they should. I'm most grateful and really appreciate your time and attention.

 

[smozgur]

I'm most grateful and really appreciate your time and attention.

You're welcome.

By the way, I also marked your post as the solution, so it will also help future readers notice this question has a working solution.