Postcode finder in Excel and caculate the distance between two postcodes

alexba

Board Regular
Joined
Nov 20, 2015
Messages
88
Hi All

I am in U.K. . I am working on a mileage expenses form for two distance from one location to another . I want intergrate postcode finder in excel . so when I enter postcode, the address will pop up. so I can caculate the distance for mileage claim.

For example: If I enter LS7 1AB, th address will be showing Lovell Park Hill,Leeds,LS7 1AB

Thanks a lot for your help in advance.

Alex
 

Excel Facts

Return population for a City
If you have a list of cities in A2:A100, use Data, Geography. Then =A2.Population and copy down.
Forgive me if I'm wrong, but I don't think Excel has the capability to calculate distances between postcodes. The only way that I'm aware of to make this possible is to have a pre-built list of postcodes with x y z co-ordinates.

You would then need to use an INDEX() of some sort to extract the two x y z co-ordinates based on your post codes being row references & sum the difference to convert into miles. Sounds quite complicated actually. I'm hoping there's an easier solution & if there is I'd love to learn it!
 
Upvote 0
Hi

I have spent a couple of hours online searching some threads regarding the postcode finder. I have got an VBA now.

But still have a bit problem with the highlighted line.



Private Sub Worksheet_Change(ByVal Target As Range)

If Target.Row = Range("postcode").Row And Target.Column = Range("postcode").Column Then
Dim IE As New InternetExplorer
IE.Visible = True
IE.navigate "http://www.royalmail.com/find-a-postcode?place=" & Range("postcode").Value
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE

Dim Doc As HTMLDocument
Set Doc = IE.document
Dim sDD As String
sDD = Trim(Doc.getElementsByTagName("<div title")(1).innerText)[/B]
Dim aDD As Variant
aDD = Split(sDD, ",")
Range("postcode").Value = aDD(1)



End If

End Sub


Please can someone help me .

Kind regards

Alex
 
Upvote 0
Hi,
I played with this ages ago and just found the file , so I thought I would share it with you.
I can't recall where I got the info from but I just tested it again and it appears to work fine

setup your data like this

[TABLE="width: 344"]
<tbody>[TR]
[TD]Location 1[/TD]
[TD]Location 2[/TD]
[TD]Km[/TD]
[TD]Miles[/TD]
[/TR]
[TR]
[TD]LS7 1AB[/TD]
[TD]LS1 3AD[/TD]
[TD]2.0[/TD]
[TD]1.2[/TD]
[/TR]
[TR]
[TD]LS7 1AB[/TD]
[TD]LS2 9JT[/TD]
[TD]2.0[/TD]
[TD]1.3[/TD]
[/TR]
[TR]
[TD]LS7 1AB[/TD]
[TD]LS8 2LJ[/TD]
[TD]4.8[/TD]
[TD]3.0[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]0.0[/TD]
[TD]0.0[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]0.0[/TD]
[TD]0.0[/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD]0.0[/TD]
[TD]0.0[/TD]
[/TR]
</tbody>[/TABLE]

In cell C2 use this UDF formula
Code:
=G_Distance(A2,B2)

In a new module paste this UDF
Code:
Function G_DISTANCE(Origin As String, Destination As String) As Double
Dim myRequest As XMLHTTP60
Dim myDomDoc As DOMDocument60
Dim distanceNode As IXMLDOMNode
    G_DISTANCE = 0
    On Error GoTo exitRoute
    Origin = Replace(Origin, " ", "%20")
    Destination = Replace(Destination, " ", "%20")
    Set myRequest = New XMLHTTP60
    myRequest.Open "GET", "http://maps.googleapis.com/maps/api/directions/xml?origin=" _
        & Origin & "&destination=" & Destination & "&sensor=false", False
    myRequest.send
    Set myDomDoc = New DOMDocument60
    myDomDoc.LoadXML myRequest.responseText
    Set distanceNode = myDomDoc.SelectSingleNode("//leg/distance/value")
    If Not distanceNode Is Nothing Then G_DISTANCE = distanceNode.Text / 1000
exitRoute:
    Set distanceNode = Nothing
    Set myDomDoc = Nothing
    Set myRequest = Nothing
End Function

The answer is in Km but just multiply the answer by 0.621371 to get it to miles

Paul.
 
Upvote 0
Hi,
I played with this ages ago and just found the file , so I thought I would share it with you.
I can't recall where I got the info from but I just tested it again and it appears to work fine

Hi - I get User-defined type not defined at:

Dim myRequest As XMLHTTP60

1606910260243.png



I guess the current versions of Excel (I'm using 365) use a different xml protocol or something?
 
Upvote 0
Addressing the issue above, the compile error went away when I ticked "Microsoft XML v6.0" from Tools...References... in the VBA editor.

But for me the function till returns only zero. Can anybody help me understand why?


1606911141371.png






1606910893083.png
 
Upvote 0
Hi,
Yes, it worked in 2016 but Google have changed things since then.
As far as I know, you will need to register your credit card with Google in order to get an API key (that was enough to put me off). They offer quite a lot of free usage calls but if you exceed their limits you get charged.
There was another request recently, link below. It may be worth following it up.

Also do a general search on this board, I recall several threads relating to distance finding using Google and Bing
 
Upvote 0
Thanks, indeed I spent a couple of hours searching and found yours to be the most up-to-date or other's pointing to yours! Thanks anyway.
 
Upvote 0
Hi,
Try this one

It uses Bing maps and you will need to obtain your own API key.
I think if you exceed your usage limits, Bing will probably block further usage until your next quota, whereas Google prefer to charge you.
Good luck
Paul.
 
Upvote 0

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