Possible nested functions?

peterderrington

New Member
Joined
Aug 6, 2019
Messages
26
Office Version
  1. 2019
Platform
  1. Windows
Hi,

I'm sure what I'm trying to achieve is easy but my brains not in gear today....

I have a spread sheet which contains 2 rows (E and I) that each have a date stamp in them, what I want to do is calculate if the two dates are on the same day and if so return a value.

I firstly tried =DATEDIF(E3,I3,"D") which returns either a 0,1 or #NUM !

What I was wanting was to tidy up that response, to 0 = True, 1 = False and #NUM ! = Blank

I came close when I referenced the cell that the above formula was in like this: =IFERROR(Z3<1,"No")

But I'm guessing that I need to somehow nest the two formulas together.

Can anyone help?

Thanks
 

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excel store dates as number, e.g. today 6th Aug 2019 is 43682, so compare dates is just compare numbers.

a simple =if(E3=I3, 0,1) should do it
 
Upvote 0
As Alan has rightly stated, Excel stores dates as numbers (01/01/1900 being 1) and then every day after that date increments the value by 1.

For future reference, you will return a #NUM ! error with the DATEDIF function when your 2nd date parameter is before​ the first date parameter.
 
Upvote 0
Nope, that hasn't worked, it returns 0 in every field.

The two fields are time stamps (sorry) so for example E3= 04/08/2019 17:55:00 and I3= 04/08/2019 08:31:02

Now in theory the value in I3 SHOULD always be before the value in E3 but it wont always
 
Upvote 0
you can use the int() function to take out the time value as stored in fraction of a day, try

=if(int(E3)=int(I3),0,1)
 
Upvote 0
So close, with a small alteration I'm almost there: =IF(INT(E3)=INT(I3), "True","False")

Now ideally I'd like to return a blank for all those values that result in a #NUM ! value originally (because there's no value in row I)
 
Upvote 0
can try

=iferror(IF(INT(E3)=INT(I3), "True","False"),"")
 
Upvote 0

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