Passing a formula with a variable

Beneindias

Board Regular
Joined
Jun 21, 2022
Messages
120
Office Version
  1. 365
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  2. MacOS
Hi guys.

I will try to explain my problem.

I have an excel file with 2 worksheets.

In worksheet 1, I have a table with a column that has a function that goes to worksheet 2, and finds a value in a table.

In this table, I have column with various numbers, but there are two rows with a formula, for example 14*2*(100 - R) where "R" is a value that I have in worksheet 1, in cell $BB9.

Can I have that "R" value pointing to my $BB9 cell and doing the calculations? Or do I need to "hard code" this formula?

So, to simplify:
Worksheet1!A2 -> =worksheet2!D1 [can be D2, D3, D4, it depends]

Worksheet2!D1 = 14*2*(100 - worksheet1!BB9) [it can be BB10, BB11, depends on the table row]

Can anibody help me, please?

Thanks
 

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Hi,
If my understanding is correct, you need Indirect ...
you can test following:
Excel Formula:
=14*2*(100-INDIRECT("sheet1!BB"&ROW()+8))
 
Upvote 0
Hi,
If my understanding is correct, you need Indirect ...
you can test following:
Excel Formula:
=14*2*(100-INDIRECT("sheet1!BB"&ROW()+8))
I think that it's no exactly what I wanted.

This is part os my table in worksheet 1:

Cell Formulas
RangeFormula
BB9:BB10BB9=[@[Total Vencimento Base]]+[@[Total Retroativos]]+[@[Total Horas Extra]]+[@[Total Prémios]]
BC9:BC10BC9=IF(Retencoes!$C$6="","Colocar taxa na página de retenções",Retencoes!$C$6)
BD9:BD10BD9=[@[Total Valores Sujeitos a Desconto]]*[@[Taxa Seg. Social]]
BE9:BE10BE9=IFERROR(INDEX(Tabela1,MATCH(Salarios!$BB9,Tabela1[Remuneração],0),3),IFERROR(INDEX(Tabela1,MATCH(Salarios!$BB9,Tabela1[Remuneração],1)+1,3),0))
BF9:BF10BF9=IF(IFERROR(INDEX(Tabela1,MATCH(Salarios!$BB9,Tabela1[Remuneração],0),1)=2,INDEX(Tabela1,MATCH(Salarios!$BB9,Tabela1[Remuneração],1)+1,1)=2),Retencoes!$E$17,"Não")
Cells with Conditional Formatting
CellConditionCell FormatStop If True
B9:BT10Expression=$C9=VERDADEIROtextYES



This is my table in worksheet 2:

vencimentos v2.4.3 - 2 semestre 2023.xlsm
BCDE
14Remuneração Mensal
15EscalãoRemuneraçãoTaxaParcela a abater (€)
161762,00 €0,00%0,00 €
172886,57 €14,50%14,5%*2,3*(1093,31 - R)
183932,14 €21,00%21%*1,3*(1350,22 - R)
194999,14 €21,00%114,14 €
2051 106,93 €26,50%169,09 €
2161 600,36 €28,50%191,23 €
2271 961,36 €35,00%295,26 €
2382 529,05 €37,00%334,48 €
2493 694,46 €38,72%377,86 €
25105 469,90 €40,05%427,18 €
26116 420,55 €42,72%573,22 €
271220 064,21 €44,95%716,08 €
28131 000 000,00 €47,17%1 162,51 €
Retencoes


As you can check, In worksheet 1, column BF, I have a formula that finds the right value in the table that I have in worksheet 2.
The problem is that in line 2 and 3, instead of only a value, we have a formula. in this formula, the value R is the value that I have in my worksheet's 1 column BB.
So, I was looking to have this R dynamic, when it's used in table of worksheet1.

the value R will vary depending on the row in table of worksheet 1.
 
Upvote 0

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