Object variable or With block variable not set

tiredofit

Well-known Member
Joined
Apr 11, 2013
Messages
1,924
Office Version
  1. 365
  2. 2019
Platform
  1. Windows
Standard module:

Rich (BB code):
Dim MyVar(1 To 10, 1 To 10) As MyClass

Set MyVar(1 To 10, 1 To 10) = New MyClass

MyVar(1, 1).Category = "Some category"
MyVar(2, 1).Fruit = "Some fruit"

MyClass:

Rich (BB code):
Private pCategory As Variant
Private pFruit As Variant
Public Property Get Category() As Variant Category = pCategory End Property Public Property Let Category(ByVal Cat As Variant) pCategory = Cat End Property
Public Property Get Fruit() As Variant Fruit = pFruit End Property Public Property Let Fruit(ByVal F As Variant) pFruit = F End Property

This line brings up a compile and syntax error message:

Rich (BB code):
Set MyVar(1 To 10, 1 To 10) = New MyClass

so I changed it to:

Rich (BB code):
Set MyVar(10, 10) = New MyClass
then this line returns a Object variable or With block variable not set:

Rich (BB code):
MyVar(1, 1).Category = "Some category"

Can someone tell me what is wrong?

Thanks
 
Last edited:

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You initialized one element of the array (MyVar(10, 10)) as a class instance, but then tried to assign a property to an element of the array that hasn't been initialized.

You need to initialize them all.
 
Upvote 0
You initialized one element of the array (MyVar(10, 10)) as a class instance, but then tried to assign a property to an element of the array that hasn't been initialized.

You need to initialize them all.

Can you show me how to initialize them all?
 
Upvote 0
See if this does what you need

Code:
Sub aTest()
    Dim MyVar(1 To 10) As MyClass
    Dim i As Long, v As Variant
    
    For i = 1 To 10
        Set MyVar(i) = New MyClass
    Next i
    
    MyVar(1).Category = "Category1"
    MyVar(1).Fruit = "Fruit1"
    MyVar(2).Category = "Category2"
    MyVar(2).Fruit = "Fruit2"
    'Just to check...
    For Each v In MyVar
        If v.Category <> "" Then
            MsgBox v.Category
            MsgBox v.Fruit
        End If
    Next v
End Sub

M.
 
Last edited:
Upvote 0
See if this does what you need

Code:
Sub aTest()
    Dim MyVar(1 To 10) As MyClass
    Dim i As Long, v As Variant
    
    For i = 1 To 10
        Set MyVar(i) = New MyClass
    Next i
    
    MyVar(1).Category = "Category1"
    MyVar(1).Fruit = "Fruit1"
    MyVar(2).Category = "Category2"
    MyVar(2).Fruit = "Fruit2"
    'Just to check...
    For Each v In MyVar
        If v.Category <> "" Then
            MsgBox v.Category
            MsgBox v.Fruit
        End If
    Next v
End Sub

M.

Thanks, will check it and get back to you shortly.

BTW, can you explain why this errors (as I initially mentioned)?

Rich (BB code):
Set MyVar(1 To 10, 1 To 10) = New MyClass



 
Upvote 0
You cannot set all array elements at once. Loop does the job by setting one at each step.

M.
 
Upvote 0
By the way, this worked for me

Code:
Sub aTest()
    [COLOR=#ff0000]Dim MyVar(1 To 10) As New MyClass
[/COLOR]    Dim i As Long, v As Variant
        
    MyVar(1).Category = "Category1"
    MyVar(1).Fruit = "Fruit1"
    MyVar(2).Category = "Category2"
    MyVar(2).Fruit = "Fruit2"
    MyVar(10).Category = "Category10"
    MyVar(10).Fruit = "Fruit10"
    
    'Just to check..
    For Each v In MyVar
        If Not v Is Nothing Then
            MsgBox v.Category
            MsgBox v.Fruit
        End If
    Next v
End Sub

M.
 
Upvote 0
You cannot set all array elements at once. Loop does the job by setting one at each step.

I see but why does this compile?

Rich (BB code):
Set MyVar(10, 10) = New MyClass


By the way, this worked for me

Code:
Sub aTest()
    [COLOR=#ff0000]Dim MyVar(1 To 10) As New MyClass
[/COLOR]    Dim i As Long, v As Variant
        
    MyVar(1).Category = "Category1"
    MyVar(1).Fruit = "Fruit1"
    MyVar(2).Category = "Category2"
    MyVar(2).Fruit = "Fruit2"
    MyVar(10).Category = "Category10"
    MyVar(10).Fruit = "Fruit10"
    
    'Just to check..
    For Each v In MyVar
        If Not v Is Nothing Then
            MsgBox v.Category
            MsgBox v.Fruit
        End If
    Next v
End Sub

M.

Thanks, I checked and it worked.
 
Upvote 0

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