Number formatting into Sets of 3

anthonyexcel

Active Member
Joined
Jun 10, 2011
Messages
258
Office Version
  1. 365
Platform
  1. Windows
I have numbers in column A that look like this
[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD]13,065,102[/TD]
[/TR]
[TR]
[TD]13,165[/TD]
[/TR]
[TR]
[TD]4,051,065[/TD]
[/TR]
[TR]
[TD]600[/TD]
[/TR]
[TR]
[TD]18,013,092[/TD]
[/TR]
</tbody>[/TABLE]



But when I click in the formula bar they are really this (real numbers)
[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD]13065102[/TD]
[/TR]
[TR]
[TD]13165[/TD]
[/TR]
[TR]
[TD]4051065[/TD]
[/TR]
[TR]
[TD]600[/TD]
[/TR]
[TR]
[TD]18013092[/TD]
[/TR]
</tbody>[/TABLE]


What I need to do is to is put the numbers into sets of 3 from right to left
[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD]13065102[/TD]
[TD]013[/TD]
[TD]065[/TD]
[TD]102[/TD]
[/TR]
[TR]
[TD]13165[/TD]
[TD]013[/TD]
[TD]165[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]4051065[/TD]
[TD]004[/TD]
[TD]051[/TD]
[TD]065[/TD]
[/TR]
[TR]
[TD]600[/TD]
[TD]600[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]18013092[/TD]
[TD]018[/TD]
[TD]013[/TD]
[TD]092[/TD]
[/TR]
</tbody>[/TABLE]
 

Excel Facts

Get help while writing formula
Click the italics "fx" icon to the left of the formula bar to open the Functions Arguments dialog. Help is displayed for each argument.
Using vba:

Code:
Sub a1110422a()
Dim c As Range, j As Long
Columns("B:D").NumberFormat = "@"
    For Each c In Range("A2", Cells(Rows.count, "A").End(xlUp))
        j = 0
        For Each x In Split(c.text, ",")
        j = j + 1: c.Offset(, j) = Format(x, "000")
        Next
    Next
End Sub


Excel 2013/2016
ABCD
1
213,065,102013065102
313,165013165
44,051,065004051065
5600600
618,013,092018013092
Sheet1
<p style="width:4.8em;font-weight:bold;margin:0;padding:0.2em 0.6em 0.2em 0.5em;border: 1px solid rgb(187,187,187);border-top:none;text-align: center;background-color: rgb(218,231,245);color: rgb(22,17,32)">Sheet2</p><br /><br />
 
Upvote 0
Number in A2
Please try at B2:D2
=MID(TEXT($A2,REPT(0,CEILING(LEN($A2),3))),COLUMNS($B2:B2)*3-2,3)
 
Upvote 0
A little simpler formula...

=MID(TEXT($A2,"000000000"),3*COLUMNS($B:B)-2,3)

600 need to be on the left, that where I use REPT(0,CEILING(LEN($A2),3)) instead of "000000000"



[TABLE="class: cms_table_grid, width: 500"]
<tbody>[TR]
[TD]13065102[/TD]
[TD]013[/TD]
[TD]065[/TD]
[TD]102[/TD]
[/TR]
[TR]
[TD]13165[/TD]
[TD]013[/TD]
[TD]165[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]4051065[/TD]
[TD]004[/TD]
[TD]051[/TD]
[TD]065[/TD]
[/TR]
[TR]
[TD]600[/TD]
[TD]600[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]18013092[/TD]
[TD]018[/TD]
[TD]013[/TD]
[TD]092[/TD]
[/TR]
</tbody>[/TABLE]
 
Upvote 0
Edit: Ooops, hadn't seen post 5

A little simpler formula...

=MID(TEXT($A2,"000000000"),3*COLUMNS($B:B)-2,3)
Problem is it doesn't do what Bo-Ry's does or what the OP requested. ;)
 
Last edited:
Upvote 0
Another formula option is to use different formula for the 3 columns, keeping the formulas much simpler.
Each formula copied down.

Excel Workbook
ABCD
213065102013065102
313165013165
44051065004051065
5600600
618013092018013092
Sets of 3




If the numbers can be longer than 9 digits & you have the CONCAT function then ..
B2 copied down
C2 copied across and down

Excel Workbook
ABCDEF
256989513065102056989513065102
33003
44051065004051065
5600000000000600000000000
618013092018013092
Sets of 3 (2)
 
Last edited:
Upvote 0
Hi,
I would suggest
Code:
Sub test()
    Dim a, b As Variant
    lr = Cells(Rows.Count, 2).End(xlUp).Row - 1
    a = Application.Transpose(Range("b2").Resize(lr))
    Application.ScreenUpdating = False
    ReDim b(1 To 1)
    With CreateObject("VBScript.RegExp")
        .Global = True
        .Pattern = "\d+"
        For i = 1 To lr
            Set Sres = .Execute(a(i))
            ReDim b(1 To Sres.Count)
            For j = 0 To Sres.Count - 1
                b(j + 1) = Formt(Sres(j),"000")
            Next
            Range("c" & i + 1).Resize(, UBound(b)) = b
        Next
    End With
    Application.ScreenUpdating = True
End Sub
 
Last edited:
Upvote 0
Small modi
Just add the colored line
Code:
a = Application.Transpose(Range("b2").Resize(lr))
[COLOR=#ff0000]    Range("c2:e" & lr).Resize(lr).NumberFormat = "000"[/COLOR]
    Application.ScreenUpdating = False
 
Upvote 0

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