Hi all,
I'm sure the solution to this is easy, but I cannot work it out nor find the solution on the board.
I have 2 columns...
What I need to do is:
For each staff member
- If they have element 1z, they must also have element 3x
- If they have 2y, they must have 4w
- If they have 5v, they must have 6u
So staff number C3 would fail as they do not have "1z and 3y" or "5v and 6u"
Thank you muchly for any help!
I'm sure the solution to this is easy, but I cannot work it out nor find the solution on the board.
I have 2 columns...
Code:
Staff Element
A1 1z
A1 2y
A1 3x
A1 4w
A1 5v
A1 6u
A1 7t
A1 8s
B2 1z
B2 2y
B2 3x
B2 4w
B2 5v
B2 6u
B2 7t
B2 8s
C3 1z
C3 2y
C3 4w
C3 5v
C3 7t
C3 8s
What I need to do is:
For each staff member
- If they have element 1z, they must also have element 3x
- If they have 2y, they must have 4w
- If they have 5v, they must have 6u
So staff number C3 would fail as they do not have "1z and 3y" or "5v and 6u"
Thank you muchly for any help!