Need normal formula instead volatile

motilulla

Well-known Member
Joined
Feb 13, 2008
Messages
2,422
Office Version
  1. 2010
Hello,</SPAN>

At present using following volatile formula does it is possible to be converted in the normal formula</SPAN></SPAN>


Book1
EFG
1
2
33 | 0 | 0 | 2 | 2 | 2 | 1 | 1 | 13
Sheet1
Cell Formulas
RangeFormula
G3=MATCH(1000,INDEX(FIND(" | "&ROW(INDIRECT("1:999"))&" | "," | "&E3&" | "),0))


Thank you all</SPAN></SPAN>

Excel 2000</SPAN></SPAN>
Regards,</SPAN></SPAN>
Moti</SPAN></SPAN>
 
Last edited:

Excel Facts

Select a hidden cell
Somehide hide payroll data in column G? Press F5. Type G1. Enter. Look in formula bar while you arrow down through G.
Just remove the volatile function.

=MATCH(1000,INDEX(FIND(" | "&ROW($1:$999)&" | "," | "&E3&" | "),0))

It will work as long as you're not in the habit of deleting rows.
 
Upvote 0
Just remove the volatile function.

=MATCH(1000,INDEX(FIND(" | "&ROW($1:$999)&" | "," | "&E3&" | "),0))

It will work as long as you're not in the habit of deleting rows.
jasonb75, it is running fine thank you very much for your help</SPAN></SPAN>

Kind Regards,
</SPAN>
Moti
</SPAN>
 
Upvote 0
Hi, here's a version that remains robust against row insertion and deletion.

=MATCH(1000,INDEX(FIND(" | "&ROW(INDEX(G:G,1):INDEX(G:G,999))&" | "," | "&E3&" | "),0))
 
Upvote 0
Hi, here's a version that remains robust against row insertion and deletion.

=MATCH(1000,INDEX(FIND(" | "&ROW(INDEX(G:G,1):INDEX(G:G,999))&" | "," | "&E3&" | "),0))
FormR, tried it is also running fine, I noticed the difference in your formula clicking on formula bar this highlights only the column G instead of all area, thank you so much for your help</SPAN></SPAN>

Kind Regards,
</SPAN>
Moti
</SPAN></SPAN>
 
Upvote 0
If you're trying to make the formula more efficient then you could remove the array concatenation as well, the formula would still work correctly.

=MATCH(1000,INDEX(FIND(ROW($G$1:$G$999),E3),0))

If your original data only ever contains single digit numbers then you don't need $999 as the end row, $9 will suffice. This is probably the biggest improvement that you could make.

The method suggested by FormR is only needed if you're in the habit of deleting rows, if you don't delete rows then the index union is not necessary.
 
Upvote 0
If you're trying to make the formula more efficient then you could remove the array concatenation as well, the formula would still work correctly.

=MATCH(1000,INDEX(FIND(ROW($G$1:$G$999),E3),0))

If your original data only ever contains single digit numbers then you don't need $999 as the end row, $9 will suffice. This is probably the biggest improvement that you could make.

The method suggested by FormR is only needed if you're in the habit of deleting rows, if you don't delete rows then the index union is not necessary.
jasonb75, really I do not delete any rows, tested your formula rectified $9 it is working well. Thank you for shorting it.</SPAN></SPAN>


Book1
EFG
1
2
33 | 0 | 0 | 2 | 2 | 2 | 1 | 1 | 13
Sheet1
Cell Formulas
RangeFormula
G3=MATCH(1000,INDEX(FIND(ROW($G$1:$G$9),E3),0))


Kind Regards,
</SPAN>
Moti
</SPAN></SPAN>
 
Last edited:
Upvote 0
Hi, If it's just single digit numbers you can also hard code them and maintain robustness (which I personally consider to be important, even if you don't intend to insert or delete rows).

=MATCH(1000,INDEX(FIND({1,2,3,4,5,6,7,8,9},E3),0))
 
Upvote 0
Solution
Hi, If it's just single digit numbers you can also hard code them and maintain robustness (which I personally consider to be important, even if you don't intend to insert or delete rows).

=MATCH(1000,INDEX(FIND({1,2,3,4,5,6,7,8,9},E3),0))
FormR, I also consider this one is the best solution of my problem!</SPAN></SPAN>

I appreciate your help
</SPAN></SPAN>

Kind Regards,
</SPAN>
Moti :)
</SPAN>


 
Last edited:
Upvote 0

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