ScottTemple
Board Regular
- Joined
- Dec 28, 2023
- Messages
- 103
- Office Version
- 365
- Platform
- Windows
Hello,
I have a workbook that is pulling data in from a Power Query, that I am creating a Pivot Table from. I would like to create a third tab in the workbook to create an interactive dashboard, without using VBA/Macros. What I am attempting to create is that when I select the 'All Shavers' checkbox, data is pulled from the pivot table to encompass all the different Shaver numbers (1-7, minus 6). In addition, I would like to select any one, or multiple Shavers, so the data populated under the Shaver headers only return data based on what is selected, and those Shaver's not select remain blank (see below examples). The second example does not have any correct formulas, I just copied/pasted based on what I am looking to create.
If anyone has some suggestions, or ideally some YouTube videos that showcase more than just the basic uses for Radio/Checkmark buttons, I would be greatful.
Formula in cell C5: =INDEX('Pivot Table'!$B$12:$C$17,ROWS('Pivot Table'!$A$12:A12),$A$1)
I have a workbook that is pulling data in from a Power Query, that I am creating a Pivot Table from. I would like to create a third tab in the workbook to create an interactive dashboard, without using VBA/Macros. What I am attempting to create is that when I select the 'All Shavers' checkbox, data is pulled from the pivot table to encompass all the different Shaver numbers (1-7, minus 6). In addition, I would like to select any one, or multiple Shavers, so the data populated under the Shaver headers only return data based on what is selected, and those Shaver's not select remain blank (see below examples). The second example does not have any correct formulas, I just copied/pasted based on what I am looking to create.
If anyone has some suggestions, or ideally some YouTube videos that showcase more than just the basic uses for Radio/Checkmark buttons, I would be greatful.
Formula in cell C5: =INDEX('Pivot Table'!$B$12:$C$17,ROWS('Pivot Table'!$A$12:A12),$A$1)