Multiple for each loop on different ranges inside each other

CsJHUN

Active Member
Joined
Jan 13, 2015
Messages
360
Office Version
  1. 365
  2. 2021
  3. 2019
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  2. Mobile
Hi guys, i would like to identify one row on a table with multiple merged cells in multiple column. Imagine something like this:
Ashok L. 300-7 round PC v1 DFMEA control prevention új.xlsx
ABCDEFGHIJK
1Col ACol BCol CCol DCol ECol FCol GCol HCol ICol JCol K
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
Munka2


to identify the row the data has to be the same in (for exapmple) col A, Col B, Col D, Col E, Col F. However Col F is not merged and should not contain merged cells, but the values within the cells could be the same, but different content of Col A, B, D, E, F. I hope that makes sense.

I started with for each loop from left to right
VBA Code:
Dim cell_a as Range, cell_b as range...
...
'assing values for identifying row
t_find_a = "blahbla1"
t_find_b = "blahbla2"
t_find_d = "blahbla3"
t_find_e = "blahbla4"
t_find_f = "blahbla5"

'now opening the another workbook where i need to identify the row
set findfile = workbook.open(t_findfile_path)
lra = range("A" & rows.count).end(xlup).row
for each cell_a in findfile.sheets(1).range("A10:A" & lra)
if cell_a_value = t_find_a then
cell_b_start = cell_a.row
cell_b_area = cell_a.mergearea.count -1
'this sould narrow the search for column b
for each cell_b in range(cells(cell_b_start, "B"), cells(cell_b_start+cell_b_area , "B")
cell_d_start = cell_b.row
cell_b_area= cell_b.mergearea.count -1
for each cell_d...
....
..
next cell_d
next cell_b
next cell_a
so finding the first column rows, then finding the 2.nd column rows, within 1st, then 3rd rows, within 2nd, .... eventualy identify the row.
Then if i have the row, i have to check the values within the cells(merged or not) if it has the same value as the original file ( from which i started the macro)#for
But still gives me errors, sometimes 400, object not valid, object error.

Any solution? What did i wrong? What is missing?
 
Last edited by a moderator:

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