Modifying S-Curve to accept starting value

kcmuppet

Active Member
Joined
Nov 2, 2005
Messages
439
Office Version
  1. 365
Platform
  1. Windows
Hi

This formula, generates a value a point on a S-curve (B13 at this point =1, the first period)
Excel Formula:
=Peak_value/(1+EXP(-((LN(1/pc_Peak_at_Hypergrowth_start-1)-LN(1/pc_Peak_at_Hypergrowth_end-1))/(Hypergrowth_end-Hypergrowth_start))*
(B13-(LN(1/pc_Peak_at_Hypergrowth_start-1)/((LN(1/pc_Peak_at_Hypergrowth_start-1)-
LN(1/pc_Peak_at_Hypergrowth_end-1))/(Hypergrowth_end-Hypergrowth_start))+Hypergrowth_start))))
1684312191114.png


It is possible to modify it so that it accepts a starting value (5% in the example below), rather than distributing the values in the example here:
S-Curve modified.xlsx
ABCDEFGHIJKLMNOPQRSTU
1Starting percentage5%
2Peak100%
3Hypergrowth starts ~ period6
4% of Peak at Hypergrowth start25%
5Hypergrowth ends ~ period10
6% of Peak at Hypergrowth end point70%
7
8
9
10
11
12
13Period:1234567891011121314151617181920
14Value at point on curve with existing formula:2.8%4.5%7.2%11.2%17.0%25.0%35.2%46.9%58.9%70.0%79.1%86.1%90.9%94.2%96.4%97.7%98.6%99.1%99.5%99.7%
15Desired value with modified formula:5.0%???????????????????
Sheet1
Cell Formulas
RangeFormula
B14:U14C14=Peak_value/(1+EXP(-(( LN(1/pc_Peak_at_Hypergrowth_start-1)- LN(1/pc_Peak_at_Hypergrowth_end-1))/(Hypergrowth_end-Hypergrowth_start))* (C13-( LN(1/pc_Peak_at_Hypergrowth_start-1)/(( LN(1/pc_Peak_at_Hypergrowth_start-1)- LN(1/pc_Peak_at_Hypergrowth_end-1))/(Hypergrowth_end-Hypergrowth_start))+Hypergrowth_start))))
B13:U13B13=SEQUENCE(1,20)
B15B15=Start_value
Dynamic array formulas.
Named Ranges
NameRefers ToCells
Hypergrowth_end=Sheet1!$B$5B14:U14
Hypergrowth_start=Sheet1!$B$3B14:U14
pc_Peak_at_Hypergrowth_end=Sheet1!$B$6B14:U14
pc_Peak_at_Hypergrowth_start=Sheet1!$B$4B14:U14
Peak_value=Sheet1!$B$2B14:U14
Start_value=Sheet1!$B$1B15


(The maths are explained here, but I'm unable to make contact with the originator)
 

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