Macro - Working except it's skipping Line 3

rroth2004

New Member
Joined
Sep 23, 2013
Messages
8
Copied around an existing Macro I found online. Where it searches the data on sheet 1 for a name in column E and then pastes it into the corresponding sheet in the workbook.
It works great and moves all the data over except it leaves Line 3 (A3) of the Data for some reason. If I run the macro a second time, it'll sort that last item just fine.
But wondering where in the code I'm skipping Line 3 in Sheet1?
Below is the truncated example of the code. I have the meat of the code duplicated multiple times based on Last Name and Sheet #.

Any help?

Sub Sort_Date()

Dim StatusCol As Range
Dim Status As Range
Dim PasteCell As Range

Set StatusCol = Sheet1.Range("E2:E300")

For Each Status In StatusCol

If Sheet2.Range("A2") = "" Then
Set PasteCell = Sheet2.Range("A2")
Else
Set PasteCell = Sheet2.Range("A1").End(xlDown).Offset(1, 0)
End If

If Status = "SMITH" Then Status.Offset(0, -4).Resize(1, 15).Cut PasteCell

Next Status

End Sub
 

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Instead of looping through column E, why not just filter the column on "SMITH" and cut/paste the visible range?
 
Upvote 0
Instead of looping through column E, why not just filter the column on "SMITH" and cut/paste the visible range?
I'm actually looping thru multiple names. Just posted the one "Smith" as an example. The full code is the above - times maybe 13 or 14 sheets/different names.
Probably not the cleanest way of doing it but I'm still learning.
 
Upvote 0
Rather the asking for help using only one name, it is better to describe in full what you want to do so that you end up with a final solution. It would be easier to help if you could upload a copy of your file to a free site such as www.box.com or www.dropbox.com. Once you do that, mark it for 'Sharing' and you will be given a link to the file that you can post here. Explain in detail what you want to do referring to specific cells, rows, columns and sheets using a few examples from your data (de-sensitized if necessary).
 
Upvote 0
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