looping vba vlookup column index number

tomwax46

New Member
Joined
May 22, 2022
Messages
1
Office Version
  1. 2016
  2. 2013
Platform
  1. Windows
hey,hope you are doing great, the below code matches the first column between 2 workbooks then copy & paste the matched results using vlookup function, the problem is that vlookup only shows 1 cell result while i need the whole row to be copied so i tried to loop the process to chnage column index number step by step but it doesn't seem to work. any help or tip would be really appreciated.

VBA Code:
Sub solution()

Dim oldRow As Integer
Dim newRow As Integer
Dim lrow_output As Integer
Dim WB_Input As Workbook
Dim WB_Output As Workbook
Dim WS_Input As Worksheet
Dim WS_Output As Worksheet
Dim funcStr As String
Dim i As Integer

Set WB_Input = Workbooks("File.xlsm")
Set WB_Output = Workbooks("output1.xlsx")

Set WS_Input = WB_Input.Worksheets("input")
Set WS_Output = WB_Output.Worksheets("Sheet1")

With WS_Output
    lrow_output = .Cells(.Rows.Count, 1).End(xlUp).Row
End With

With WS_Input
For i = 2 To 3 Step 1
    funcStr = "=IFERROR(VLOOKUP(" & Cells(1, 1).Address(False, False) & "," & "'[" & WB_Input.Name & "]" & .Name & "'!" & Range(.Columns(1), .Columns("B:Z")).Address & ",i,0),"""")"

With WS_Output
    .Cells(1, i).Formula = funcStr
    .Cells(1, i).Copy
    Range(.Cells(1, i), .Cells(lrow_output, i)).PasteSpecial xlPasteFormulas
    WS_Output.Calculate
    Range(.Cells(1, i), .Cells(lrow_output, i)).Copy
    Range(.Cells(1, i), .Cells(lrow_output, i)).PasteSpecial xlPasteValues
    Application.CutCopyMode = False
    End With
    
Next i
End With
End Sub
 

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