Lookup value in table, return the cell above

yits05

Board Regular
Joined
Jul 17, 2020
Messages
56
Office Version
  1. 2016
Platform
  1. Windows
Hello,

This is probably simple but I can't seem to figure this out. I would like a formula that looks up the value in A1 to find the match in a table, say d5:J20, and return the cell directly above the matched cell.

Any advice would be appreciated.
 

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If you use Index Match, you find the Row using Match then just subtract the number of rows you need to get the row you actually want.
In the case of 1 row before, you might want to include the header row in your range in case what you find is in the first data row.

In the below I have used cell for to get the row, but you could either hard code that or use a match to work out the Column as well.

1616457115511.png


20210323 Index Match offset 1 row.xlsx
ABCDEFGHIJK
130
2
3Return Value
4Column NoCol1Col2Col3Col4Col5Col6Col7
5222010210310410510610710
6332020220320420520620720
730230330430530630730
840240340440540640740
950250350450550650750
1060260360460560660760
11
Workings
Cell Formulas
RangeFormula
B5:B6B5=INDEX($D$4:$J$10, MATCH($A$1,$D$4:$D$10,0)-1,$A5)
 
Upvote 0
If you use Index Match, you find the Row using Match then just subtract the number of rows you need to get the row you actually want.
In the case of 1 row before, you might want to include the header row in your range in case what you find is in the first data row.

In the below I have used cell for to get the row, but you could either hard code that or use a match to work out the Column as well.

View attachment 35044

20210323 Index Match offset 1 row.xlsx
ABCDEFGHIJK
130
2
3Return Value
4Column NoCol1Col2Col3Col4Col5Col6Col7
5222010210310410510610710
6332020220320420520620720
730230330430530630730
840240340440540640740
950250350450550650750
1060260360460560660760
11
Workings
Cell Formulas
RangeFormula
B5:B6B5=INDEX($D$4:$J$10, MATCH($A$1,$D$4:$D$10,0)-1,$A5)
Thank you, Alex.

Just to clarify, however, the lookup value may be in any column in the table. So, for example, as below I would want like a formula that would populate in B2:B4 that search for the values in A2:A4, and returns the cell above. Thanks again

Value to SearchResult:Column1Column2Column3
abcipsumhelloipsumfiller
defworldworldabctext
ghiheredefloremhere
randomwordghi
 
Upvote 0
Are you only looking at a very small number of columns ? If so it would be possible using that concept with IFS.
If its a large number of columns or needs to be scalable, I will have a look but we may need to look to someone else to come up with some suggestions.

Is a helper column acceptable ?
 
Upvote 0
Are you only looking at a very small number of columns ? If so it would be possible using that concept with IFS.
If its a large number of columns or needs to be scalable, I will have a look but we may need to look to someone else to come up with some suggestions.

Is a helper column acceptable ?
Hi, yes, helper column is totally fine. There wont be more than ~6 columns.
 
Upvote 0
Here is one way (assuming values can only occur once in Column1:Column3)

21 03 23.xlsm
ABCDEF
1Value to SearchResult:Column1Column2Column3
2abcipsumhelloipsumfiller
3defworldworldabctext
4ghiheredefloremhere
5randomwordghi
Cell above
Cell Formulas
RangeFormula
B2:B4B2=INDEX(D:F,AGGREGATE(15,6,ROW(D$2:F$5)/(D$2:F$5=A2),1)-1,AGGREGATE(15,6,(COLUMN(D$2:F$5)-COLUMN(D2)+1)/(D$2:F$5=A2),1))
 
Upvote 0

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