LOOKUP result vector error

shane23 · Feb 14, 2024

I have an issue with a LOOKUP function where the result vector is showing an incorrect value, but only for a specific lookup vector. There are 66 rows in the table but only one row has the incorrect value.

The value are related to time.

Cheers

awoohaw · Feb 14, 2024

It seems to work for me. Not sure why you have the same value repeating in your lookup column though.
You may want to share your formula. It is pretty hard to debug when the forum doesn't have all the information.
Please use the xl2bb add in to share, the link to the add in is below.

Book1

A

B

C

D

E

1

0

2

6.7

6

0

3

6.85

6.25

7.7

7

4

7

6.5

9

8.5

5

7.15

6.75

6

7.3

7

7.45

7.25

8

7.55

6.75

9

7.7

7

10

7.7

7

11

7.85

7.25

12

8

7.5

13

9

8.5

Sheet6

Cell Formulas
Range	Formula
E2:E4	E2	=LOOKUP(D2,$A$1:$A$13,$B$1:$B$13)

Alex Blakenburg · Feb 14, 2024

If you really have time underlying those figures then the chances are that you have a rounding / precision issue.
If you have 365 why not use XLookup instead of Lookup and then you can put a rounding function around your lookup range and lookup value.

Using the awoohaw XL2BB data that he kindly provided in E2 something like this:

Excel Formula:

=XLOOKUP(ROUND(D2,5),ROUND($A$1:$A$13,5),$B$1:$B$13,,-1,1)

shane23 · Feb 14, 2024

awoohaw said:
It seems to work for me. Not sure why you have the same value repeating in your lookup column though.
You may want to share your formula. It is pretty hard to debug when the forum doesn't have all the information.
Please use the xl2bb add in to share, the link to the add in is below.

Book1
A B C D E
1 0 0
2 6.7 6 0 0
3 6.85 6.25 7.7 7
4 7 6.5 9 8.5
5 7.15 6.75
6 7.3 7
7 7.45 7.25
8 7.55 6.75
9 7.7 7
10 7.7 7
11 7.85 7.25
12 8 7.5
13 9 8.5
Sheet6
Cell Formulas
Range Formula
E2:E4 E2 =LOOKUP(D2,$A$1:$A$13,$B$1:$B$13)

Hi,

Thank you for the reply. I tested a smaller lookup on another tab in the spreadsheet and still had the same issue, however can provide more details on the formula etc as per your reply. Sorry I have not used xl2bb add in, i've moved to my Mac and can't seem to install it/

I have pasted the formula bar and as you can see by the highlighted cell, I'm still getting the same incorrect value. What i didn't put in my OP is that the "shift" value is a result of a formula.

H14=G14-F14

If i just type 7.7 into this cell, i actually receive the correct result vector of 7!

Screen Shot 2024-02-15 at 10.15.24 am.png

awoohaw · Feb 14, 2024

Are H14 and G14 values or formulas? Have you expaned the number decimal to Maximum in all 3 cells?

shane23 · Feb 14, 2024

awoohaw said:
Are H14 and G14 values or formulas? Have you expaned the number decimal to Maximum in all 3 cells?

F14 and G14 are keyed values. i.e. F14 is shift start time and G14 is shift end time and H14 is the formula mentioned above, which gives the shift length time of 7.7 hours. Because this does not equate correctly, that is where i am using the lookup. I am only seeing this error with this particular lookup, as 6.7 and 8.7 give the correct result of 6 and 8 (hours) respectively.

awoohaw · Feb 14, 2024

I've replicated your error. I even did a Match(K4:K34,H14,0) and MATCH(H14,K4:K35,0); and got all NA# errors. But, when I did H14=7.7 it resolved to TRUE.
This is quite a conundrum, my guess is that it is a floating decimal issue that happens. But, I am not expert on that nor know how to resolve other than using the ROUND function in your formula.

Excel Formula:

=LOOKUP(ROUND(H14,2),ROUND(K4:K35,2),L4:L35)

Book1

F

G

H

I

J

K

L

1

2

3

4

#N/A

0.00000000000000E+00

5

#N/A

3.00000000000000E+00

6

#N/A

3.15000000000000E+00

3.25000000000000E+00

7

#N/A

3.30000000000000E+00

3.50000000000000E+00

8

#N/A

3.45000000000000E+00

3.75000000000000E+00

9

#N/A

3.55000000000000E+00

3.25000000000000E+00

10

#N/A

3.70000000000000E+00

3.50000000000000E+00

11

#N/A

3.85000000000000E+00

3.75000000000000E+00

12

#N/A

4.00000000000000E+00

13

Start

Finish

Shift

Return

#N/A

4.15000000000000E+00

4.25000000000000E+00

14

8.300000000000000

16.000000000000000

7.70000000000000E+00

7.250000000000000

#N/A

4.30000000000000E+00

4.50000000000000E+00

15

#N/A

4.45000000000000E+00

4.75000000000000E+00

16

#N/A

4.70000000000000E+00

4.25000000000000E+00

17

#N/A

4.85000000000000E+00

4.50000000000000E+00

18

#N/A

5.00000000000000E+00

4.75000000000000E+00

19

#N/A

5.15000000000000E+00

5.00000000000000E+00

20

#N/A

5.30000000000000E+00

5.25000000000000E+00

21

#N/A

5.45000000000000E+00

5.50000000000000E+00

22

#N/A

5.70000000000000E+00

5.75000000000000E+00

23

#N/A

5.85000000000000E+00

5.25000000000000E+00

24

#N/A

6.00000000000000E+00

5.50000000000000E+00

25

#N/A

6.15000000000000E+00

5.75000000000000E+00

26

#N/A

6.30000000000000E+00

6.00000000000000E+00

27

#N/A

6.45000000000000E+00

6.25000000000000E+00

28

#N/A

6.70000000000000E+00

6.50000000000000E+00

29

#N/A

6.85000000000000E+00

6.75000000000000E+00

30

#N/A

7.00000000000000E+00

6.25000000000000E+00

31

#N/A

7.15000000000000E+00

6.50000000000000E+00

32

#N/A

7.30000000000000E+00

6.75000000000000E+00

33

#N/A

7.45000000000000E+00

7.00000000000000E+00

34

#N/A

7.70000000000000E+00

7.25000000000000E+00

35

#N/A

7.85000000000000E+00

7.50000000000000E+00

Sheet1

Cell Formulas
Range	Formula
I4	I4	=MATCH(H14,K4:K35,0)
J4:J35	J4	=MATCH(K4:K35,H14,0)
H14	H14	=G14-F14
I14	I14	=LOOKUP(ROUND(H14,2),ROUND(K4:K35,2),ROUND(L4:L35,2))
Dynamic array formulas.

shane23 · Feb 14, 2024

awoohaw said:
I've replicated your error. I even did a Match(K4:K34,H14,0) and MATCH(H14,K4:K35,0); and got all NA# errors. But, when I did H14=7.7 it resolved to TRUE.
This is quite a conundrum, my guess is that it is a floating decimal issue that happens. But, I am not expert on that nor know how to resolve other than using the ROUND function in your formula.

Excel Formula:

=LOOKUP(ROUND(H14,2),ROUND(K4:K35,2),L4:L35)

Book1
F G H I J K L
1
2
3
4 #N/A #N/A 0.00000000000000E+00 0.00000000000000E+00
5 #N/A 3.00000000000000E+00 3.00000000000000E+00
6 #N/A 3.15000000000000E+00 3.25000000000000E+00
7 #N/A 3.30000000000000E+00 3.50000000000000E+00
8 #N/A 3.45000000000000E+00 3.75000000000000E+00
9 #N/A 3.55000000000000E+00 3.25000000000000E+00
10 #N/A 3.70000000000000E+00 3.50000000000000E+00
11 #N/A 3.85000000000000E+00 3.75000000000000E+00
12 #N/A 4.00000000000000E+00 4.00000000000000E+00
13 Start Finish Shift Return #N/A 4.15000000000000E+00 4.25000000000000E+00
14 8.300000000000000 16.000000000000000 7.70000000000000E+00 7.250000000000000 #N/A 4.30000000000000E+00 4.50000000000000E+00
15 #N/A 4.45000000000000E+00 4.75000000000000E+00
16 #N/A 4.70000000000000E+00 4.25000000000000E+00
17 #N/A 4.85000000000000E+00 4.50000000000000E+00
18 #N/A 5.00000000000000E+00 4.75000000000000E+00
19 #N/A 5.15000000000000E+00 5.00000000000000E+00
20 #N/A 5.30000000000000E+00 5.25000000000000E+00
21 #N/A 5.45000000000000E+00 5.50000000000000E+00
22 #N/A 5.70000000000000E+00 5.75000000000000E+00
23 #N/A 5.85000000000000E+00 5.25000000000000E+00
24 #N/A 6.00000000000000E+00 5.50000000000000E+00
25 #N/A 6.15000000000000E+00 5.75000000000000E+00
26 #N/A 6.30000000000000E+00 6.00000000000000E+00
27 #N/A 6.45000000000000E+00 6.25000000000000E+00
28 #N/A 6.70000000000000E+00 6.50000000000000E+00
29 #N/A 6.85000000000000E+00 6.75000000000000E+00
30 #N/A 7.00000000000000E+00 6.25000000000000E+00
31 #N/A 7.15000000000000E+00 6.50000000000000E+00
32 #N/A 7.30000000000000E+00 6.75000000000000E+00
33 #N/A 7.45000000000000E+00 7.00000000000000E+00
34 #N/A 7.70000000000000E+00 7.25000000000000E+00
35 #N/A 7.85000000000000E+00 7.50000000000000E+00
Sheet1
Cell Formulas
Range Formula
I4 I4 =MATCH(H14,K4:K35,0)
J4:J35 J4 =MATCH(K4:K35,H14,0)
H14 H14 =G14-F14
I14 I14 =LOOKUP(ROUND(H14,2),ROUND(K4:K35,2),ROUND(L4:L35,2))
Dynamic array formulas.

Thank you. I'm glad it wasn't only me having this issue.

I will have a go at using the ROUND function.

awoohaw · Feb 14, 2024

shane23 said:
Thank you. I'm glad it wasn't only me having this issue.
I will have a go at using the ROUND function.

You're welcome. I reviewed some of the Floating Point Decimal documentation on the Excel web site. It can catch you in situations where you think it not problem. This is one of those circumstances.

Best wishes.

Alex Blakenburg · Feb 14, 2024

So did you try my suggestion in Post #3 ?

LOOKUP result vector error

shane23

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