Looking to find the cell returning the first number greater than 1 and return the column header for that cell

[smiley359]

I've got my column headers as dates Column C:N and my rows 2-3 contain the numbers. I'd like to find the cell in row 2 that first reached a number >=1 and return the date in column header.
I'd like to have Column T return the column header for the cell that first meets my criteria.

My formula is =IFERROR(LOOKUP(2,1/(c2:S2>1),C1:S1),"")
but it returns the last column header for the cell that last met the criteria and not the first cell meeting my criteria.
T2 should return 5/1/21 and T3 should return 9/1/21
What am I doing wrong?

 

[Tetra201]

See if the following array formula works for you:

=IFERROR(INDEX($C$1:$S$1,MATCH(TRUE,C2:S2>1,0)),"")

 

[smiley359]

See if the following array formula works for you:

=IFERROR(INDEX($C$1:$S$1,MATCH(TRUE,C2:S2>1,0)),"")

That works! Thanks for your help!

 

[Tetra201]

You are welcome.

 

[Peter_SSs]

Since you have Microsoft 365, you could also use the new FILTER function.. In your original question you said >=1 (though I note your thread title does not) so I have used that.

22 04 24.xlsm
	C	D	E	F	G	H	I	J	K	L	M	N	O	P	Q	R	S	T
1	5/01/21	6/01/21	7/01/21	8/01/21	9/01/21	10/01/21	11/01/21	12/01/21	1/01/22	2/01/22	3/01/22	4/01/22	5/01/22	6/01/22	7/01/22	8/01/22	9/01/22
2	2	2	2	2	2	2	2	3	3	3	3	3						5/01/21
3	0	0	0	1	2	8	11	11	11	11	11	11						8/01/21
4	0	0	0	0	0	0	0	0	0	0	0	0
5	0	5	0	5	0	5	0	5	0	5	0	5						6/01/21
Earliest Date

Cell Formulas
Range	Formula
T2:T5	T2	=INDEX(FILTER(C$1:S$1,C2:S2>=1,""),1)