Looking to expand a VBA Macro / Pick random cell from column

peejaygee

New Member
Joined
Jul 23, 2006
Messages
40
Hey All,

So, I have a list of items in a column, that I'd like to randomly pick from.

I have a very basic routine, that picks on, and highlights the column a based on what it picks. But,

I'd like to be able to randomly pick, but if it's already been picked before to not pick it again, I'm guessing by checking the colour of the cell?

At the moment, I have this

Sub FindRandomCell()
Dim ColumnA As Long
Dim StartRow As Long
Dim HeaderRow As Long
Dim LastRow As Long
Dim randomNum As Long
ColumnA = 1
HeaderRow = 1
StartRow = 3
LastRow = Cells(Rows.Count, 1).End(xlUp).Row
randomNum = WorksheetFunction.RandBetween(StartRow, LastRow)
Cells(randomNum, ColumnA).Interior.Color = RGB(0, 255, 0)
Cells(randomNum, ColumnA).Select
End Sub

Any thoughts would be appreciated.

Thanks.
 
Last edited:

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When they said you are going to "Excel at life", they meant you "will be doing Excel your whole life".
Try this:-
Code:
[COLOR="Navy"]Sub[/COLOR] MG27Mar41
[COLOR="Navy"]Dim[/COLOR] Lastrow [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long,[/COLOR] RandomNum [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long,[/COLOR] c [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long[/COLOR]
Lastrow = Cells(Rows.Count, 1).End(xlUp).Row
RandomNum = WorksheetFunction.RandBetween(3, Lastrow)
DoEvents
[COLOR="Navy"]Do[/COLOR] [COLOR="Navy"]While[/COLOR] Cells(RandomNum, "A").Interior.Color = RGB(0, 255, 0)
    RandomNum = WorksheetFunction.RandBetween(3, Lastrow)
    c = c + 1
    [COLOR="Navy"]If[/COLOR] c > Lastrow [COLOR="Navy"]Then[/COLOR] [COLOR="Navy"]Exit[/COLOR] [COLOR="Navy"]Sub[/COLOR]
[COLOR="Navy"]Loop[/COLOR]
 
Cells(RandomNum, "A").Interior.Color = RGB(0, 255, 0)
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]Sub[/COLOR]
Regards Mick
 
Upvote 0
Thank you, that did the trick.

I added in Cells(randomNum, "A").Select so it jumps to the cell and it's now perfect. :)
 
Upvote 0

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