Is there any way to access the trendline parameters in cell expressions?

JenniferMurphy

Well-known Member
Joined
Jul 23, 2011
Messages
2,676
Office Version
  1. 365
Platform
  1. Windows
If I have a chart with a trendline, is there any way that I can use the trendline parameters in cell expressions?

The chart on the right plots the Conf column on the Y axis against the #Reviews column on the X axis. I found that a power series trendline matches almost perfectly. Now I want to use that equation to find the value for Conf based on other #Reviews values. To do that, I need the parameters of the power equation (coefficient = 1.2421 & exponent = -0.498).

I don't see any way to access those parameters in a cell equation. Is there any way?

1683742547171.png


Suppose I want
 

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I saw a recent video by My Online Training Hub recently that used the LINEST function to return the trendline co-efficients.
this is what I get when I use that with your data. I hope this gives some help:

I think the first value is the slope and the 2nd is the y intercept.

Book1
ABCD
1Rtg#ReviewsRankConf
25946710.0132
33910120.0130
44849930.0136
5574440.0445
6444450.0608
7342760.0625
858870.1328
945680.1673
1033990.2045
1149100.4081
1254110.6270
1332120.8727
14
15=LINEST(D2:D13,B2:B13)
16-3.30607E-050.297899387
JenniferMurphy
Cell Formulas
RangeFormula
A15A15=FORMULATEXT(A16)
A16:B16A16=LINEST(D2:D13,B2:B13)
Dynamic array formulas.
 
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There is also a LOGEST function for exponental charts . and maybe that will work with logarithms too.
 
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I saw a recent video by My Online Training Hub recently that used the LINEST function to return the trendline co-efficients.
The LINEST function fits a linear equation to the data. My data closely fits a power equation. A linear equation is not useful. I added a linear trendline to my chart. It shows the same parameters as you reported. I need the parameters for a power equation trendline.

1683749101327.png


PS: The linear trendline on the chart is not a straight line, because the X axis is logarithmic.
 
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The LINEST function fits a linear equation to the data. My data closely fits a power equation. A linear equation is not useful. I added a linear trendline to my chart. It shows the same parameters as you reported. I need the parameters for a power equation trendline.

View attachment 91393

PS: The linear trendline on the chart is not a straight line, because the X axis is logarithmic.
yes, i figured that. The LOGEST may work better for you.
 
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Maybe this will help. The link below shows how to calculate a power trendline in Excel (formula is near the bottom of the page).

Book1
ABCDEFG
1Rtg#ReviewsRankConf
25946710.01321.242679332
33910120.013-0.498242034
44849930.0136
5574440.0445
6444450.0608
7342760.0625
858870.1328
945680.1673
1033990.2045
1149100.4081
1254110.627
1332120.8727
Sheet2
Cell Formulas
RangeFormula
G2G2=EXP(INDEX(LINEST(LN(D2:D13),LN(B2:B13),,),1,2))
G3G3=INDEX(LINEST(LN(D2:D13),LN(B2:B13),,),1)
 
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Solution
Maybe this will help. The link below shows how to calculate a power trendline in Excel (formula is near the bottom of the page).

That works perfectly. Thanks.

I will never remember that expression, so I'd like to put in a UDF. Is there a way that I can use those expressions in VBA without putting application.worksheet in front of each function call?
 
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My knowledge of VBA is limited. Hopefully someone else can help you with a UDF.
 
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