If you look in the image I attached, I am trying to get the 0 in cell Z6, with the formula shown, to be input into cell AC6. At times Column 6 may have up to four numbers depending on what number i assign to the corresponding cell in the "Engine Formulas" tab.Do you have a good sense of humor bamacwby? The reason I ask is because I wanted to be flippant as a response to you statement above because you're not asking a question. Usually I don't respond to these kinds of posts. The title of the thread is a question, but between the title and the statement I can't make sense of the request.
A formula cannot change the values of other cells. A series of formulas could read a single cell and break it into different sections based on a delimiter or other rules.
Can you please be more specific.
Jeff
Cell Formulas | ||
---|---|---|
Range | Formula | |
Z6,Z7:AC7 | Z6 | =IF(LEN('Engine Formulas'!E4)=0,0,MID('Engine Formulas'!E4,SEQUENCE(,LEN('Engine Formulas'!E4)),1)) |
Cell Formulas | ||
---|---|---|
Range | Formula | |
X6:AC8 | X6 | =LET(s,REPT(" ",6-LEN('Engine Formulas'!E4))&'Engine Formulas'!E4,MID(s,SEQUENCE(,LEN(s),),1)) |
Dynamic array formulas. |
AutoTraining.xlsm | |||||
---|---|---|---|---|---|
D | E | F | |||
4 | 0 | ||||
5 | 123 | ||||
6 | 9365 | ||||
7 | |||||
Engine Formulas |
That still puts the 0 in cell Z6. I need the 0 in cell AC6 and if the number in cell "Engine Formulas E4 is 911, I need the numbers to start in cell AC6 and go right to leftAre you saying you want to display a zero if Cell 'Engine Formulas'!E4 has no value, otherwise you want to display each number in 'Engine Formulas'!E4 across Z6:AC6?
Cell Formulas Range Formula Z6,Z7:AC7 Z6 =IF(LEN('Engine Formulas'!E4)=0,0,MID('Engine Formulas'!E4,SEQUENCE(,LEN('Engine Formulas'!E4)),1))
@bamacwby I'm thinking you need formula like below?
Cell Formulas Range Formula X6:AC8 X6 =LET(s,REPT(" ",6-LEN('Engine Formulas'!E4))&'Engine Formulas'!E4,MID(s,SEQUENCE(,LEN(s),),1)) Dynamic array formulas.
AutoTraining.xlsm
D E F 4 0 5 123 6 9365 7 Engine Formulas
HTH