Index Row header

Rolly_Sefu

Board Regular
Joined
Oct 25, 2013
Messages
149
Hello I have a table (my table will never start from A1)

For ex: I have the nr 13 and column name "Sat"

And I need the row header: "Alan"

unfortunately I can not use : =Index(E8:E10,Match(("13",G7:F10,0)) because I get an error.

[TABLE="class: grid, width: 500"]
<tbody>[TR]
[TD][/TD]
[TD]E[/TD]
[TD]G[/TD]
[TD]E[/TD]
[TD]F[/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD][/TD]
[TD]Fri[/TD]
[TD]Sat[/TD]
[TD]Sun[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]Alan[/TD]
[TD]20[/TD]
[TD]13[/TD]
[TD]4[/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]James[/TD]
[TD]7[/TD]
[TD]5[/TD]
[TD]9[/TD]
[/TR]
[TR]
[TD]10[/TD]
[TD]Karla[/TD]
[TD]12[/TD]
[TD]15[/TD]
[TD]10[/TD]
[/TR]
</tbody>[/TABLE]

Any ideas for a good and simple formula ?

Thank you
 

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Use a custom number format of #,##0,K. Each comma after the final 0 will divide the displayed number by another thousand

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