=if(or()) with another workbook

[bloodybrit90]

With the following formula I keep receiving #Value.

=IF(OR('[NEF.xls]NEFAR MASTER LIST'!$C$90:$C$96='Sheet2'!D2),'Sheet2'!E2,"")

I would like it to return the value from E2 if D2 value is equal to any of the numbers between C90 and C96, if not do nothing. Any ideas why this is not working?

 

[pplstuff]

The way you have typed it, it needs to be an array. (crtl+shift+enter)

 

[lmvk99]

I think the prob is an IF statement doesn't loop through an array. Try this instead:

=IF(IFERROR(MATCH(Sheet2!D2,'[NEF.xls]NEFAR MASTER LIST'!$C$90:$C$96,0),"")>0,Sheet2!E2,"")

Good Luck!

 

[bloodybrit90]

(crtl+shift+enter) removes the #value but does not return values that should be correct.

 

[bloodybrit90]

PPlstuff, With the formula you provided I receive an error message stating that "You've entered too many arguments for this function". Any ideas why?

 

[T. Valko]

With the following formula I keep receiving #Value.

=IF(OR('[NEF.xls]NEFAR MASTER LIST'!$C$90:$C$96='Sheet2'!D2),'Sheet2'!E2,"")

I would like it to return the value from E2 if D2 value is equal to any of the numbers between C90 and C96, if not do nothing. Any ideas why this is not working?

PPlstuff, With the formula you provided I receive an error message stating that "You've entered too many arguments for this function". Any ideas why?

When entered as an array formula** the above formula works OK for me.

** array formulas need to be entered using the key
combination of CTRL,SHIFT,ENTER (not just ENTER).
Hold down both the CTRL key and the SHIFT key
then hit ENTER.