=IF Exact formula stops working part way through

tabbytomo

New Member
Joined
Jun 23, 2016
Messages
18
Afternoon, I have a rather lengthy formula that stops working about half way through. Values 1 Tablet - 27 Tablets work, 1, 2 and 0 boxes work. But 29 - 55 Tablets don't work and I can't understand why!

So if I pop any of the corresponding values in AF, for example 1.9642857142857100, it should return "55 Tablets", but I receive the 'Something has broken' fail message instead.

Excel Formula:
=IF(EXACT(AF3,"0.0357142857142857"),"1 Tablet",IF(EXACT(AF3,"0.0714285714285714"),"2 Tablets",IF(EXACT(AF3,"0.107142857142857"),"3 Tablets",IF(EXACT(AF3,"0.142857142857143"),"4 Tablets",IF(EXACT(AF3,"0.178571428571429"),"5 Tablets",IF(EXACT(AF3,"0.214285714285714"),"6 Tablets",IF(EXACT(AF3,"0.25"),"7 Tablets",IF(EXACT(AF3,"0.285714285714286"),"8 Tablets",IF(EXACT(AF3,"0.321428571428571"),"9 Tablets",IF(EXACT(AF3,"0.357142857142857"),"10 Tablets",IF(EXACT(AF3,"0.392857142857143"),"11 Tablets",IF(EXACT(AF3,"0.428571428571429"),"12 Tablets",IF(EXACT(AF3,"0.464285714285714"),"13 Tablets",IF(EXACT(AF3,"0.5"),"14 Tablets",IF(EXACT(AF3,"0.535714285714286"),"15 Tablets",IF(EXACT(AF3,"0.571428571428571"),"16 Tablets",IF(EXACT(AF3,"0.607142857142857"),"17 Tablets",IF(EXACT(AF3,"0.642857142857143"),"18 Tablets",IF(EXACT(AF3,"0.678571428571429"),"19 Tablets",IF(EXACT(AF3,"0.714285714285714"),"20 Tablets",IF(EXACT(AF3,"0.75"),"21 Tablets",IF(EXACT(AF3,"0.785714285714286"),"22 Tablets",IF(EXACT(AF3,"0.821428571428571"),"23 Tablets",IF(EXACT(AF3,"0.857142857142857"),"24 Tablets",IF(EXACT(AF3,"0.892857142857143"),"25 Tablets",IF(EXACT(AF3,"0.928571428571429"),"26 Tablets",IF(EXACT(AF3,"0.964285714285714"),"27 Tablets",IF(EXACT(AF3,"1.0357142857142900"),"29 Tablets",IF(EXACT(AF3,"1.0714285714285700"),"30 Tablets",IF(EXACT(AF3,"1.1071428571428600"),"31 Tablets",IF(EXACT(AF3,"1.1428571428571400"),"32 Tablets",IF(EXACT(AF3,"1.1785714285714300"),"33 Tablets",IF(EXACT(AF3,"1.21428571428571"),"34 Tablets",IF(EXACT(AF3,"1.2500000000000000"),"35 Tablets",IF(EXACT(AF3,"1.2857142857142900"),"36 Tablets",IF(EXACT(AF3,"1.3214285714285700"),"37 Tablets",IF(EXACT(AF3,"1.3571428571428600"),"38 Tablets",IF(EXACT(AF3,"1.3928571428571400"),"39 Tablets",IF(EXACT(AF3,"1.4285714285714300"),"40 Tablets",IF(EXACT(AF3,"1.4642857142857200"),"41 Tablets",IF(EXACT(AF3,"1.5000000000000000"),"42 Tablets",IF(EXACT(AF3,"1.5357142857142900"),"43 Tablets",IF(EXACT(AF3,"1.5714285714285700"),"44 Tablets",IF(EXACT(AF3,"1.6071428571428600"),"45 Tablets",IF(EXACT(AF3,"1.6428571428571400"),"46 Tablets",IF(EXACT(AF3,"1.6785714285714300"),"47 Tablets",IF(EXACT(AF3,"1.7142857142857200"),"48 Tablets",IF(EXACT(AF3,"1.7500000000000000"),"49 Tablets",IF(EXACT(AF3,"1.7857142857142900"),"50 Tablets",IF(EXACT(AF3,"1.8214285714285700"),"51 Tablets",IF(EXACT(AF3,"1.8571428571428600"),"52 Tablets",IF(EXACT(AF3,"1.8928571428571400"),"53 Tablets",IF(EXACT(AF3,"1.9285714285714300"),"54 
Tablets",IF(EXACT(AF3,"1.9642857142857100"),"55 Tablets",IF(EXACT(AF3,"1"),"1 Box",IF(EXACT(AF3,"2"),"2 Boxes",IF(EXACT(AF3,"0"),"0 Boxes/ Tablets","Something has broken!")))))))))))))))))))))))))))))))))))))))))))))))))))))))))
 

Excel Facts

Format cells as time
Select range and press Ctrl+Shift+2 to format cells as time. (Shift 2 is the @ sign).
Your formula searches for text strings. When you enter a value is it a number ( right-aligned in cell when no manual alignment applied) or text ( left aligned)?
In the first case, your cell should be formatted as text
BTW building a small lookup table with one column with values and the other with resulting text would be easier to handle. You just need a VLOOKUP or INDEX/MATCH or XLOOKUP to retrieve your text
 
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