Alright guys… im struggling with this one, maybe I’ve been looking at it for too long…
Background….
Panel A DOES Not have a built in Comm Card, but…
Panel B has a built in Comm Card,
Both panels can have multiple Comm Cards, the number of Comm Cards is dependent on the number of Com Devices, each Comm card can accommodate 100 Comm devices
If I have 392 Comm devices, then panel B needs 4 Comm Cards and Panel A needs 3 (because Panel A does not include one built in).
Here’s the catch, there are 2 different Comm Cards and they work in pairs, Master & Slave.
So…
if I’m using Panel A, with 392 Comm devices, then I need 2 Masters & 2 Slaves
If I’m using Panel B, with 392 Comm devices, then I need 1 Master and 2 Slaves (because Panel B had 1 master card built in)
If I’m using Panel B, with 092 Comm devices, then I don’t need any additional Comm Cards (because Panel B had 1 master card built in)
If I’m using Panel B, with 192 Comm devices, then I need 1 Slave (because Panel B had 1 master card built in)
Workbook…
C8 is the Panel A selected
C9 is the Panel B selected
C68 is the qty of Master Comm Cards
C69 is the qty of Slave Comm Cards
D70 is the total number of Comm devices counted (arrived from a sum total elsewhere on the worksheet)
D72 is the total number of Comm Cards needed (essentially D70/100 rounded up)
So….
If C8=1 (Panel A is selected), and D70=392, then D72=4, then C68 should be 2 and C69 should be 2
If C9=1 (Panel B is selected), and D70=392, then D72=4, then C68 should be 1 and C69 should be 2 (because C68 is the Master Comm Card and 1 is already built into Panel B)
Im burned out on this one and could use help…..
Thank you....
Background….
Panel A DOES Not have a built in Comm Card, but…
Panel B has a built in Comm Card,
Both panels can have multiple Comm Cards, the number of Comm Cards is dependent on the number of Com Devices, each Comm card can accommodate 100 Comm devices
If I have 392 Comm devices, then panel B needs 4 Comm Cards and Panel A needs 3 (because Panel A does not include one built in).
Here’s the catch, there are 2 different Comm Cards and they work in pairs, Master & Slave.
So…
if I’m using Panel A, with 392 Comm devices, then I need 2 Masters & 2 Slaves
If I’m using Panel B, with 392 Comm devices, then I need 1 Master and 2 Slaves (because Panel B had 1 master card built in)
If I’m using Panel B, with 092 Comm devices, then I don’t need any additional Comm Cards (because Panel B had 1 master card built in)
If I’m using Panel B, with 192 Comm devices, then I need 1 Slave (because Panel B had 1 master card built in)
Workbook…
C8 is the Panel A selected
C9 is the Panel B selected
C68 is the qty of Master Comm Cards
C69 is the qty of Slave Comm Cards
D70 is the total number of Comm devices counted (arrived from a sum total elsewhere on the worksheet)
D72 is the total number of Comm Cards needed (essentially D70/100 rounded up)
So….
If C8=1 (Panel A is selected), and D70=392, then D72=4, then C68 should be 2 and C69 should be 2
If C9=1 (Panel B is selected), and D70=392, then D72=4, then C68 should be 1 and C69 should be 2 (because C68 is the Master Comm Card and 1 is already built into Panel B)
Im burned out on this one and could use help…..
Thank you....