Identify product that have different values with a spilled formula

ED38

New Member
Joined
Mar 29, 2024
Messages
26
Office Version
  1. 365
Platform
  1. Windows
Hello All,

Once again I am requesting your support :)

FOr a list of product in cell col G, I have a list of associated values in col H and J with a number of occurences different from a product code to another.
I would like a spilled formula to identify the product that have always the same value1 and value2 (like product A111, B803) vs those having different values (like A063, b476, A080...).
I thought about using the standard deviation (STDEV.P) to do that but have hard time to make it work, so coming to you...
if you have other idea , no pb, stdev.p is just a proxi here.

thank you

Book3
GHIJK
1ProductValue1value2Sum of the 2 STDev.P
2A0637870560,8986837could a spilled formula do that?
3A0638180560,8986837
4A06315600560,8986837
5A06322230560,8986837
6A06313960560,8986837
7A06314270560,8986837
8A06318430560,8986837
9A06326170560,8986837
10A06316690560,8986837
11B476130210289,8295835
12B476133910289,8295835
13B47614560289,8295835
14B47620220289,8295835
15A1115000
16A1115000
17B80331600
18A11016400
19A08052021,5
20A0809021,5
21A081010050
22A081020050
Sheet1
Cell Formulas
RangeFormula
J2J2=STDEV.P(H2:H10)+STDEV.P(I2:I10)
J3:J10,J12:J14,J16,J20,J22J3=J2
J11J11=STDEV.P(H11:H14)+STDEV.P(I11:I14)
J15,J19,J21J15=STDEV.P(H15:H16)+STDEV.P(I15:I16)
J17:J18J17=STDEV.P(H17)+STDEV.P(I17)
 

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Hi DazCD,

Thank you for your attempt, but unfortunately it does not match, actually I am expecting a spilled formula what would :
- either provide the same resulat as the values in column J
- either a false when the value is >0 in J and true when the value =0 in J
does it clarify?
 
Upvote 0
but you gave me an idea using unique and I solved it myself , thank you ;-)
here is my solution in cell K2 : (no need to use the stdev calculation on top!)

Book3
GHIJK
1ProductValue1value2Sum of the 2 STDev.Pcould a spilled formula do that?
2A0637870560,8986837FALSE
3A0638180560,8986837FALSE
4A06315600560,8986837FALSE
5A06322230560,8986837FALSE
6A06313960560,8986837FALSE
7A06314270560,8986837FALSE
8A06318430560,8986837FALSE
9A06326170560,8986837FALSE
10A06316690560,8986837FALSE
11B476130210289,8295835FALSE
12B476133910289,8295835FALSE
13B47614560289,8295835FALSE
14B47620220289,8295835FALSE
15A1115000TRUE
16A1115000TRUE
17B80331600TRUE
18A11016400TRUE
19A08052021,5FALSE
20A0809021,5FALSE
21A081010050FALSE
22A081020050FALSE
Sheet1
Cell Formulas
RangeFormula
K2:K22K2=BYROW(G2:G22,LAMBDA(x,IF(ROWS(UNIQUE(FILTER(G2:I22,G2:G22=x),FALSE))=1,TRUE,FALSE)))
J2J2=STDEV.P(H2:H10)+STDEV.P(I2:I10)
J3:J10,J12:J14,J16,J20,J22J3=J2
J11J11=STDEV.P(H11:H14)+STDEV.P(I11:I14)
J15,J19,J21J15=STDEV.P(H15:H16)+STDEV.P(I15:I16)
J17:J18J17=STDEV.P(H17)+STDEV.P(I17)
Dynamic array formulas.
 
Upvote 0
Solution

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