How to split time by a setted date?

Romney

New Member
Joined
Apr 9, 2022
Messages
1
Office Version
  1. 365
Platform
  1. Windows
Hi,
I have a lot of remote camera data, and I would like to calculate the working hours of each camera in each season.

I divide a year into two seasons: the breeding season (Apr - Aug), and the non-breeding season (Sep - Mar).

Column J (Working hours) shows the total working hours, which are calculated by (F2-D2)*24+(G2-E2).

1649594663922.png


Here is the problem. Some cameras work across two seasons, such as from June to December, while some don't. In order to separate the total working hours for breeding and non-breeding season, I have to manually pick out the cameras with problems and then cut the working hour by the date "2016/9/1 00:00:00".

It will be very time-consuming because I have 700+ data. Is there any smarter method than what I did below?
1649595889833.png



Thanks a lot,
A helpless graduate student
 

Excel Facts

What is the shortcut key for Format Selection?
Ctrl+1 (the number one) will open the Format dialog for whatever is selected.
in row1 the start of every season, so 1 april and 1 septembre at 00:00:00.
There is a small difference in hours, your or my mistake ?
Map1
ABCDEFGHIJK
1start --->2016/04/012016/09/012017/04/012017/09/012018/04/01totaltotal
2startendbreedno breedbreedno breed
32016/06/034:37:482016/12/3111:59:002155:222915:5900:0000:005071:215071,35
42016/07/246:21:402016/11/155:01:02929:381805:0100:0000:002734:392734,66
52016/07/259:35:542016/09/155:01:03902:24341:0100:0000:001243:251243,42
62016/04/012018/04/013672:005088:003672:005088:0017520:0017520,00
Blad1
Cell Formulas
RangeFormula
E3:H6E3=MAX(0,MIN(F$1,$D3+$C3)-MAX($A3+$B3,E$1))
J3:J6J3=SUM(E3:H3)
K3:K6K3=+J3*24
 
Last edited:
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