How to get Graph Trendline Equation constants and read into a cell formulae automatically?

cruss

New Member
Joined
Sep 27, 2010
Messages
18
Ladies, Gents,

Is it possible to get the equation from the graph trendline and put it back into the spreadsheet to use automatically?

I am currently typing the constants manually back into some cells to be picked up and used in a formulae - a bit hopeless.

Regards

Chris
 

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Trying to understand these equations. For the 2nd Order Polynomial Trendline, what does the {1,2} refer to?
 
Upvote 0
Hi

You have in the equation

x^{1,2}

the {1,2} are the exponents, this means you have x and x^2

Think of this as what you do when you have the final values depending on 2 variables like x and y.
It just happens in this case that use the same logic but the variables are x and x^2.

With the formula you calculate the coefficients of x and x^2.

HTH
 
Upvote 0
I'm sorry but I'm still a little lost. Can I make an easy example and you show me how the formula would work/be structured? Let's say I have my named range "Y" in cells A1:C1 and my named range "X" in cells A2:C2. If I wanted to calculate the value of the first number in sequence what would the equation be? In case it's needed let's say the "X" values are 5, 10, 15.

Thanks for the help!
 
Upvote 0
Hi

This is an example

Let's say you have some (X,Y) values and you want to know the coefficients of a second degree polynomial trendline.

Y= a * X ^ 2 + b * X + c

For the example I have the (X,Y) values in A2:B6, the values of (a,b,c) in B8:B10

a: =INDEX(LINEST($B$2:$B$6,$A$2:$A$6^{1,2}),1,1)
b: =INDEX(LINEST($B$2:$B$6,$A$2:$A$6^{1,2}),1,2)
c: =INDEX(LINEST($B$2:$B$6,$A$2:$A$6^{1,2}),1,3)

We get the values (a=1,b=2,c=3)

Which means the 2nd degree trendline is:

Y= X ^ 2 + 2 * X + 3

that you can use to calculate other values of Y

Is this clear now?


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">3</td><td style="border-width:1px;border-color:#000000; padding-left:0.5em; padding-top:0.4em; padding-right:0.5em; padding-bottom:0.25em;text-align:right;border-width: 1px;border-color:#888888; "> </td></tr><tr><td style="border-width:1px;border-color:#000000; padding-left:0.5em; padding-top:0.4em; padding-right:0.5em; padding-bottom:0.25em;background:#9CF; text-align:center; " ><b>11</b></td><td style="border-width:1px;border-color:#000000; padding-left:0.5em; padding-top:0.4em; padding-right:0.5em; padding-bottom:0.25em;text-align:right;border-width: 1px;border-color:#888888; "> </td><td style="border-width:1px;border-color:#000000; padding-left:0.5em; padding-top:0.4em; padding-right:0.5em; padding-bottom:0.25em;text-align:right;border-width: 1px;border-color:#888888; "> </td><td style="border-width:1px;border-color:#000000; padding-left:0.5em; padding-top:0.4em; padding-right:0.5em; padding-bottom:0.25em;text-align:right;border-width: 1px;border-color:#888888; "> </td></tr><tr><td colspan=4 style="background:#9CF; padding-left:1em" > [Book1]Sheet1</td></tr></table>
 
Upvote 0
OK... so i did have it correct it's just for some reason the formula doesn't work when the ranges are horizontal instead of vertical. Why is that???
 
Upvote 0
I get the ending "1,2)" etc would have to change because the row/column changes but the first "1,1) formula should work correct?
 
Upvote 0
OK... so i did have it correct it's just for some reason the formula doesn't work when the ranges are horizontal instead of vertical. Why is that???

The range orientation must be othorgonal to the array of indices.

If you want to use horizontal ranges use a vertical array of indices, in this case instead of {1,2} use {1;2}

For ex. with Y values in $B$2:$F$2 and X values in $B$1:$F$1 use for the coefficient a:

a: =INDEX(LINEST($B$2:$F$2,$B$1:$F$1^{1;2}),1,1)
 
Upvote 0

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