How to create a consecutive between 2 number in excel

Saher Naji

Board Regular
Joined
Dec 19, 2019
Messages
76
Office Version
  1. 2013
Platform
  1. Windows
for example, I have 33 in cell A1, and 40 in cell B1, I want a formula in cell C1, to write an arithmetic sequence from 33 to 40 like this: 33, 34, 35, 36, 37, 38, 39, 40
1655670673015.png
 

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actually the numbers I have like this: for example: 33-38 in cell A1, I tried to right this formula: "=RIGHT(B1,2)-LEFT(A1,2)" the result will be 5, I thought that I can use this number to generate a sequence starting from 33 (5) times to reach to 38, but I did not find a formula to help me
 
Upvote 0
One way using a VBA custom function.

ExpandRange.xlsm
ABC
1334033, 34, 35, 36, 37, 38, 39, 40
Sheet3
Cell Formulas
RangeFormula
C1C1=CONSEC(A1,B1)


VBA Code:
Function CONSEC(ln As Integer, rn As Integer)
With CreateObject("Scripting.Dictionary")
    For i = ln To rn
        .Add i, True
    Next i
    CONSEC = Join(.keys, ", ")
End With
End Function
 
Upvote 0
Solution
Thanks
Is it because I don't have Office 2019, or I entered the VBA code somewhere wrong?
1655671895659.png
 
Upvote 0
No, it should work fine on 2013. You get into the VB editor by hitting Alt+F11. The go to Insert, then select Module. Paste the code there, then use the formula like normal.
 
Upvote 0
That's great, and working very well, but could I apply this into one cell, the original data I have in one column, like this:
Check column A please,
as you see I hided Columns A and B, which contain (Left) and (Right) formulas

1655675093083.png
 
Upvote 0
I'm sorry, it's working,
I used your formula with small adjustment and it's working perfect

=CONSEC(LEFT(A1,2),RIGHT(A1,2))

Thanks a lot♥
 
Upvote 0
@Irobbo314's function is what you use per your last post or have the function handle it.
If you always use 2-digits, either way will work.

Code:
Function CONSEC2(ln As Variant)
Dim rn As Integer
rn = 1 * Right(ln, Len(ln) - InStr(1, ln, "-"))
ln = 1 * Left(ln, InStr(1, ln, "-") - 1)
With CreateObject("Scripting.Dictionary")

    For i = ln To rn
        .Add i, True
    Next i
    CONSEC2 = Join(.keys, ", ")
End With
End Function
 
Upvote 0
@Irobbo314's function is what you use per your last post or have the function handle it.
If you always use 2-digits, either way will work.

Code:
Function CONSEC2(ln As Variant)
Dim rn As Integer
rn = 1 * Right(ln, Len(ln) - InStr(1, ln, "-"))
ln = 1 * Left(ln, InStr(1, ln, "-") - 1)
With CreateObject("Scripting.Dictionary")

    For i = ln To rn
        .Add i, True
    Next i
    CONSEC2 = Join(.keys, ", ")
End With
End Function
what about the formula in this case?
I tested it with the same formula, I changed it from CONSEC TO CONSEC2, but the result: (#VALUE!)
 
Upvote 0

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