How to calculate number of non-rest days YTD current year and last year?

Ironman

Well-known Member
Joined
Jan 31, 2004
Messages
1,069
Office Version
  1. 365
Platform
  1. Windows
I have kept a personal exercise log for many years and I am trying to keep myself motivated (extract below).

Column A12 contains consecutive dates exercised from 01.01.1999, and a row is added to this for every new day.

Column B12 contains exercise activity.


Mon, 8 Oct 2018 OTHER
Tue, 9 Oct 2018 OTHER
Wed, 10 Oct 2018 REST
Thu, 11 Oct 2018 REST
Fri, 12 Oct 2018 REST
Sat, 13 Oct 2018 REST
Sun, 14 Oct 2018 OTHER
Mon, 15 Oct 2018 REST
Tue, 16 Oct 2018 Viaduct
Wed, 17 Oct 2018 OTHER
Thu, 18 Oct 2018 OTHER
Fri, 19 Oct 2018 Viaduct
Sat, 20 Oct 2018 OTHER
Sun, 21 Oct 2018 OTHER
Mon, 22 Oct 2018 Viaduct
Tue, 23 Oct 2018 OTHER
Wed, 24 Oct 2018 OTHER
Thu, 25 Oct 2018 Viaduct
Fri, 26 Oct 2018 OTHER
Sat, 27 Oct 2018 OTHER
Sun, 28 Oct 2018 OTHER
Mon, 29 Oct 2018 OTHER
Tue, 30 Oct 2018 OTHER


What I'm looking for is 2 formulas that

1) Count the number of cells that do NOT contain the word REST from Jan 1 in the current year to date (e.g. to Oct 30 2018)

2) Count the number of cells that do NOT contain the word REST from Jan 1 in the previous year to date (e.g. to Oct 30 2017)

Thank you ever so much!
 
Last edited:

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On mobile so won't have whole code but in VBA you can loop through them and keep a count of how many times this holds true for if statements:
If instr(cell.value, "REST") = 0 and instr(cell.value, "2018") > 0 Then
...

If instr(cell.value, "REST") = 0 and instr(cell.value, "2017") > 0 Then
...
 
Upvote 0
Thanks RileyC but I'm just a noob and I don't know VBA.

If it helps you or anybody else, Jan 1 2017 is A6063 and Jan 1 2018 is A6428 but of course the difference won't always be 365 days due to leap years.

Thanks again.
 
Upvote 0
This year:

=COUNTIFS(A:A, ">=1/1/18", A:A, "<=" & TODAY(),B:B, "<>REST")

Last Year:

=COUNTIFS(A:A, ">=1/1/17", A:A, "<=" & EDATE(TODAY(), -12), B:B, "<>REST")
 
Last edited:
Upvote 0
Thank you so much for your time shg, that works perfectly :-)
 
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