JustSomeGuy
New Member
- Joined
- Sep 17, 2018
- Messages
- 3
Hello All,
Thanks in advance for whatever help comes my way.
I have been doing a lot of research on how to return the date of a most recent payment, unfortunately, my situation seems to be a little different than what the videos out there are showing.
Bottom line, I have a running daily column and jot down when payments come in and how much (in this instance, the amount doesn't matter).
Please see example and question below:
DATE PAYMENTS
9/1/2018 $10,000.00
9/2/2018
9/3/2018 $1,500.00
9/4/2018
9/5/2018 $7,000.00
9/6/2018
9/7/2018
9/8/2018 $6,500.00
9/9/2018
9/10/2018
9/11/2018
9/12/2018
9/13/2018
9/14/2018
9/15/2018
As stated above, my dates revolve year round, and go back to 2014, the sheet currently has over 1500 rows. I tried using a formula referencing the payment column with a function of ">0" but still couldn't get it to work properly.
Question: Given the data above, how do I have Excel tell me that the most recent payment was $6,500 and took place on 9/8/2018?
Thanks again for any help!
Thanks in advance for whatever help comes my way.
I have been doing a lot of research on how to return the date of a most recent payment, unfortunately, my situation seems to be a little different than what the videos out there are showing.
Bottom line, I have a running daily column and jot down when payments come in and how much (in this instance, the amount doesn't matter).
Please see example and question below:
DATE PAYMENTS
9/1/2018 $10,000.00
9/2/2018
9/3/2018 $1,500.00
9/4/2018
9/5/2018 $7,000.00
9/6/2018
9/7/2018
9/8/2018 $6,500.00
9/9/2018
9/10/2018
9/11/2018
9/12/2018
9/13/2018
9/14/2018
9/15/2018
As stated above, my dates revolve year round, and go back to 2014, the sheet currently has over 1500 rows. I tried using a formula referencing the payment column with a function of ">0" but still couldn't get it to work properly.
Question: Given the data above, how do I have Excel tell me that the most recent payment was $6,500 and took place on 9/8/2018?
Thanks again for any help!