Help converting two delimited columns into rows!! Arg!

Mathorik

New Member
Joined
Aug 23, 2013
Messages
4
Hello All!

I have a table with date in two columns (D&E) that have linked delimited data. If column D has 2 values separated by a "|" delimiter, then column E will have the same number of delimited values.
[TABLE="width: 500"]
<tbody>[TR]
[TD]A[/TD]
[TD]B[/TD]
[TD]C[/TD]
[TD]D[/TD]
[TD]E[/TD]
[/TR]
[TR]
[TD]51[/TD]
[TD]Bob[/TD]
[TD]PPV[/TD]
[TD]15[/TD]
[TD]9[/TD]
[/TR]
[TR]
[TD]61[/TD]
[TD]James[/TD]
[TD]CHH[/TD]
[TD]30|16|5[/TD]
[TD]17|5|8[/TD]
[/TR]
[TR]
[TD]22[/TD]
[TD]Steve[/TD]
[TD]PPV[/TD]
[TD]55|2[/TD]
[TD]-14|125[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]Ivan[/TD]
[TD]DCh[/TD]
[TD]6[/TD]
[TD]-7[/TD]
[/TR]
</tbody>[/TABLE]

I'd like the table to look like:
[TABLE="width: 500"]
<tbody>[TR]
[TD]A[/TD]
[TD]B[/TD]
[TD]C[/TD]
[TD]D[/TD]
[TD]E[/TD]
[/TR]
[TR]
[TD]51[/TD]
[TD]Bob[/TD]
[TD]ppv[/TD]
[TD]15[/TD]
[TD]9[/TD]
[/TR]
[TR]
[TD]61[/TD]
[TD]James[/TD]
[TD]CHH[/TD]
[TD]30[/TD]
[TD]17[/TD]
[/TR]
[TR]
[TD]61[/TD]
[TD]James[/TD]
[TD]CHH[/TD]
[TD]16[/TD]
[TD]5[/TD]
[/TR]
[TR]
[TD]61[/TD]
[TD]James[/TD]
[TD]CHH[/TD]
[TD]5[/TD]
[TD]8[/TD]
[/TR]
[TR]
[TD]22[/TD]
[TD]Steve[/TD]
[TD]PPV[/TD]
[TD]55[/TD]
[TD]-14[/TD]
[/TR]
[TR]
[TD]22[/TD]
[TD]Steve[/TD]
[TD]PPV[/TD]
[TD]2[/TD]
[TD]125[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]Ivan[/TD]
[TD]DCh[/TD]
[TD]6[/TD]
[TD]-7[/TD]
[/TR]
</tbody>[/TABLE]


I'd like a macro to help out, as this process will be occurring weekly with a few thousand rows...
I've seen a few examples on here- but nothing with the two linked columns.
Thank you all in advance for your brain power!

Eric
 

Excel Facts

Did you know Excel offers Filter by Selection?
Add the AutoFilter icon to the Quick Access Toolbar. Select a cell containing Apple, click AutoFilter, and you will get all rows with Apple
having your data beginning in A1, with headers, try

Code:
[COLOR=darkblue]Sub[/COLOR] trnsp()
[COLOR=darkblue]Dim[/COLOR] vArr [COLOR=darkblue]As[/COLOR] [COLOR=darkblue]Variant[/COLOR], tArr [COLOR=darkblue]As[/COLOR] [COLOR=darkblue]Variant[/COLOR], x1 [COLOR=darkblue]As[/COLOR] [COLOR=darkblue]Long[/COLOR], y1 [COLOR=darkblue]As[/COLOR] [COLOR=darkblue]Long[/COLOR], k1 [COLOR=darkblue]As[/COLOR] [COLOR=darkblue]Long[/COLOR], spltE, spltD


vArr = Range("A1").CurrentRegion.Value


[COLOR=darkblue]ReDim[/COLOR] tArr(1 [COLOR=darkblue]To[/COLOR] Evaluate(Replace("SUM(LEN(D2:D@)-LEN(SUBSTITUTE(D2:D@,""|"",""""))+1)", "@", Range("A" & Rows.Count).End(xlUp).Row)), 1 [COLOR=darkblue]To[/COLOR] 5)


[COLOR=darkblue]If[/COLOR] [COLOR=darkblue]Not[/COLOR] [COLOR=darkblue]UBound[/COLOR](vArr, 1)-1 = [COLOR=darkblue]UBound[/COLOR](tArr, 1) [COLOR=darkblue]Then[/COLOR]
    k1 = 1
    [COLOR=darkblue]For[/COLOR] x1 = [COLOR=darkblue]LBound[/COLOR](vArr, 1) + 1 [COLOR=darkblue]To[/COLOR] [COLOR=darkblue]UBound[/COLOR](vArr, 1)
        spltD = Split(vArr(x1, 4), "|")
        spltE = Split(vArr(x1, 5), "|")
        [COLOR=darkblue]For[/COLOR] y1 = [COLOR=darkblue]LBound[/COLOR](spltD) [COLOR=darkblue]To[/COLOR] [COLOR=darkblue]UBound[/COLOR](spltD)
            tArr(k1, 1) = vArr(x1, 1)
            tArr(k1, 2) = vArr(x1, 2)
            tArr(k1, 3) = vArr(x1, 3)
            tArr(k1, 4) = spltD(y1)
            tArr(k1, 5) = spltE(y1)
            k1 = 1 + k1
        [COLOR=darkblue]Next[/COLOR] y1
    [COLOR=darkblue]Next[/COLOR] x1
Range("a2").Resize(UBound(tArr, 1), 5).Value = tArr
[COLOR=darkblue]End[/COLOR] [COLOR=darkblue]If[/COLOR]

msgbox "Done"
[COLOR=darkblue]End[/COLOR] [COLOR=darkblue]Sub[/COLOR]
 
Last edited:
Upvote 0
click on Debug and put your cursor on x1 and check its value, then go back to your data and check if column D and E on Row x1 have the same number of "|"
 
Upvote 0
Found a blank value in column E on that line number. Once that was resolved, the program ran without error!
Excellent! Thank you VBA Geek!
 
Upvote 0

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